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Natali [406]
2 years ago
3

When the new book Units of Fire was released, Jonathan decided to read it in one sitting for his book report. He started at 11:0

0 a.m. on Saturday morning and read until 8:00 p.m. that night, for a total of 9 hours. For school, however, he needed to record the exact number he spent reading. What is the Order of Magnitude of the number of seconds he reads?
Mathematics
1 answer:
Deffense [45]2 years ago
3 0
9 hr * 60 min/hr = 540 min. 540 min * 60 sec/min = 32,400 sec. Use the method described by panic mode: round the number down until there is only one non-zero digit left. Here, 32,400 rounds down to 30,000. Now count the number of zeroes; the result is the order of magnitude: 4. (You see this in scientific notation also: 30,000 = 3 × 10^4.)
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Q: Angelica uses the point (4,3) to represent the location of her house and uses the point (10,8) to represent the location of a
oksian1 [2.3K]

Answer:

The answer to your question is 7.8 mi

Step-by-step explanation:

Data

H (4,3)

G (10, 8)

Process

1.- Use the distance between to points formula to find the distance

        dHG = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

x1 = 4       y1 = 3

x2 = 10    y2 = 8

2.- Substitution

         dHG = \sqrt{(10 - 4)^{2} + (8 - 3)^{2}}

3.- Simplification

         dHG = \sqrt{6^{2} + 5^{2}}

         dHG = \sqrt{36 + 25}

         dHG = \sqrt{61}

4.- Result

         dHG = 7.8 mi

4 0
2 years ago
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The density of granite is about 2.75 grams per cubic centimeter. Suppose you have a granite countertop for a kitchen that is 1 m
stellarik [79]

Answer:

330\ kg

Step-by-step explanation:

Remember that

1 kg=1,000 g

1 m= 100 cm

The volume of the granite countertop in cubic centimeters is equal to

V=(100)(300)(4)\ cm^{3}

The density in kg per cubic centimeter is equal to

D=2.75(\frac{1}{1,000}) \frac{kg}{cm^{3}}

Multiply the density by the volume

2.75(\frac{1}{1,000})(100)(300)(4)

2.75(120)=330\ kg

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2 years ago
Help quick The engineers designing the All Aboard Railroad between Boca Raton and Jupiter decide to create parallel tracks throu
QveST [7]

Answer:

Do you have answer choices

Step-by-step explanation:

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2 years ago
What types of concurrent constructions are needed to find the orthocenter of a triangle? A. intersection of the lines drawn perp
finlep [7]

Answer: Hello! The answer to your question is B, the intersection of the lines drawn to bisect each vertex of the triangle. Hope this helped! Please pick my answer as the Brainliest!

4 0
2 years ago
Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p
zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

<u>Statement 1: </u>"The pen is 3 feet wider than it is long"

Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3

------

<u>Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"</u>

Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y

------

<u>Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."</u>

Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\

------

<u>Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."</u>

Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\

Conclusion:

The systems of equations that can be used to determine the length and width of the pen and the area of the doghouse is given in Option B.

178=x^2+3x-y\\ \\ -6=4x-3y

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2 years ago
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