Question

The flow rate of the gas pump at Bob's Gas Station is 2 3 of a gallon in 1 9 of a minute. Compute the unit rate from the complex fraction 2 3 1 9 gallons per minute?

Answer 1

Answer: Unit rate would be 6 gallons per minute.

Step-by-step explanation:

Since we have given that

Part of gallon = $\dfrac{2}{3}$

Time taken  of a minute = $\dfrac{1}{9}$

We need to find the unit rate from the complex fraction i.e.

$\dfrac{\dfrac{2}{3}}{\dfrac{1}{9}}$ gallons per minute

So, it becomes,

$\dfrac{2}{3}\div \dfrac{1}{9}\\\\=\dfrac{2}{3}\times \dfrac{9}{1}\\\\=2\times 3\\\\=6\ gallons/minute$

Hence, unit rate would be 6 gallons per minute.

Answer 2

Answer:

6 gallons per min

Step-by-step explanation: