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Marizza181 [45]
2 years ago
4

Explain how to write and solve the equation.

Mathematics
3 answers:
Dmitriy789 [7]2 years ago
6 0

Answer:

$12.50 is the difference between the amount of money Sonja started with and $30. So this is a subtraction problem that can be written as 30 = s – 12.50. Undo subtraction by adding 12.50 to both sides. The answer is $42.50 thats the sample response and answer

Step-by-step explanation:

puteri [66]2 years ago
6 0
$12.50 is the difference between the amount of money Sonja started with and $30. So this is a subtraction problem that can be written as 30 = s – 12.50. Undo subtraction by adding 12.50 to both sides. The answer is $42.50. Sample Response
s344n2d4d5 [400]2 years ago
3 0

<u>Answer:</u> Sample Response: $12.50 is the difference between the amount of money Sonja started with and $30. So this is a subtraction problem that can be written as 30 = s – 12.50. Undo subtraction by adding 12.50 to both sides. The answer is $42.50.

Step-by-step explanation:

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murzikaleks [220]

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops  Price (dollars)

3         6.50

7         12.50

11         18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

Price (P) = x + (y\times \textrm{Number of Stops})

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

x+3y =6.50 \ \ \ \ equation \ 1

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

x+7y =12.50 \ \ \ \ equation \ 2

Now Subtracting equation 1 from equation 2 we get;

(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\$1.5

Substituting the value of y in equation 1 we get;

x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \$2

Hence Initial Fee is $2.

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Step-by-step explanation:

4 1
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Step-by-step explanation:

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Write down the error interval for x

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Lower bound 'd' = 186.5km

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