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2 years ago

6

Toby is making a picture graph. each picture of a book is equal to 2 bookso he has read. the row for month 1 has 3 pictures of b

ooks. how many books did Toby read during month 1

2 answers:

lozanna [386]2 years ago

8 0

It has to be nine because 2 times 3 is 9

Nata [24]2 years ago

3 0

The answer is 6 because in adding 2+2+2=6 and in multiplicating is 2*3=6

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What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.

zvonat [6]

Answer:

$x=-2.38$

$x=-4.62$

Step-by-step explanation:

The question is $(2x+3)^2+8(2x+3)+11=0$

<em>We let $u=2x+3$ , so the equation becomes:</em>

$u^2+8u+11=0$

Where $a=1, b=8, c=11$

Putting it in the quadratic formula, we have:

<u>Quadratic formula:</u> $\frac{-b+-\sqrt{b^2-4ac} }{2a}$

Substituting we have: $\frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }$

<em>We let $u=2x+3$ , so x is:</em>

<em> $u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38$ </em>

<em>and</em>

<em> $u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62$ </em>

The solutions of the equation is $x=-2.38$ (rounded to 2 decimal places), and $x=-4.62$ (rounded to 2 decimal places)

6 0

2 years ago

Last year Beth's annual salary was $38,350. This year she received a promotion and now earns $46,462 annually. She is paid biwee

kenny6666 [7]

Answer:

Quite simple. There are 52 weeks in a year. She gets paid 26 times, every other week.

38,350 / 26 = her salary from last year per check.

46,462 / 26 = her new salary per check

(46,462 - 38,350) / 26 = the difference per week

8 0

1 year ago

What is the probability that a point chosen at random in the triangle is also in the blue square? A blue square inside of an uns

Dmitrij [34]

Answer:

One-third

Step-by-step explanation:

we know that

The probability that a point chosen at random in the triangle is also in the blue square is equal to divide the area of the square by the area of triangle

step 1

Determine the area of triangle

$A=\frac{1}{2}(9)(6)=27\ in^2$

step 2

Determine the area of the square

$A=(3^2)=9\ in^2$

step 3

Determine the probability

$P=\frac{9}{27}$

simplify

$P=\frac{1}{3}$

therefore

One-third

5 0

2 years ago

After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ

icang [17]

Answer:

a) Upper Control Limit = 0.10

Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

computer manufacturer examined samples of calls to determine

the frequency of wrong advice given to callers. Each sample

consisted of 100 calls.

SAMPLE 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

Number of errors 5 3 5 7 4 6 8 4 5 9 3 4 5 6 6 7

To find - a. Determine 95 percent limits.

b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

= 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

= 0.0544

⇒P = 0.0544

Now,

Q = 1-P

= 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = $\sqrt{\frac{P.Q}{N} }$

= 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

= 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

= 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0

2 years ago

a teacher needs 70 lengths of string cut to 40 cm each. If balls of string are 10 m long how many balls will be needed

LenKa [72]

A meter is 100 cm. A ball of string has 10m of string, and you multiply 10m by 100cm, you get 1,000cm. Then you multiply 40cm by 2, and you get 80cm, or two lengths of string. Then you multiply 35, which is half of 70, by 80, and that is 2,800 cm.
2,800÷40cm=70
And 100cm=1m.
The teacher will therefore need 28 balls of string.

7 0

2 years ago