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2 years ago

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Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 43 day

s and a standard deviation of 10.1 days. Find the probability that a simple random sample of 25 protozoa will have a mean life expectancy of 46 or more days.

1 answer:

Sunny_sXe [5.5K]2 years ago

7 0

Answer: 0.0688

Step-by-step explanation:

Given : Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 43 days and a standard deviation of 10.1 days.

i.e. $\mu=43$ and $\sigma= 10.1$

Let x represents the life expectancies of a certain protozoan.

Sample size : n= 25

The probability that a simple random sample of 25 protozoa will have a mean life expectancy of 46 or more days. :-

$P(x\geq46)=1-P(x$

$=1-0.9312=0.0688$ [using z-value table]

Hence, the required probability = 0.0688

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