Question

At the SuperSpeedy drive-through the time between consecutive customer arrivals has a mean of 50 seconds and a standard deviation of 30 seconds. There are two servers whose service time averages 80 seconds with a standard deviation of 20 seconds. Assume that no customers leave the drive-through after entry. a. What is the utilization of the employees?

Answer 1

Answer:

utilization of employee is 80%

Step-by-step explanation:

Given data:

mean = 50 sec

standard deviation is 30 sec

Average number of arrivals/ sec is

$\lambda = \frac{1}{50}$

service rate id 80 sec

$\mu =\frac{1}{80}$

The utilzation of employee is calculated as

$\frac{\lambda}{c\mu} = \frac{80}{2\times 50} = 0.8$

i.e 80%

utilization of employee is 80%