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2 years ago

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You wish to test whether the number of fouls called in regular season games is different than during the NCAA tournament. The me

an number of fowls called during all regular season gams is u = 40.1 During 16 randomly selected playoff games n = 16 the mean number of fowls is 38.1 and the standard deviation of the sample = 5.8 You calculate a 95% Confidence Interval for the mean number of fouls called during playoff games The lower value of the confidence interval is:______

1 answer:

kolezko [41]2 years ago

7 0

Answer:

the lower value of the interval = 35.26

Step-by-step explanation:

The mean number is u = 40.1

n = 16

the mean number called x is 38.1

the standard deviation = 5.8

given a 95% Confidence Interval

The lower value of the confidence interval is?

<u>solution</u>

There is a inﬁnite population and the standard deviation of the population is known,

the below formula is used for determining an estimate of the conﬁdence limits of the population mean, i.e.

x ± ( zₐσ)/ √n

For a 95% conﬁdence level, the value of za is taken from the confidence interval table = 1.96.

the conﬁdence limits of the population=

x ± ( zₐσ)/ √n

38.1 ± (1.96*5.8)/ √16

38.1 ± 11.368/4

38.1 ± 2.842

40.942 or 35.258

Thus, the 95% conﬁdence limits are 40.942 or 35.258

this prediction is made with conﬁdence that it will be correct nine five times out of 100.

finally, the lower value of the interval = 35.26

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Subtract (7.8 - 5.1t) from (2.8 - 3.2t). Use

tankabanditka [31]

Answer: we can use the commutative property to show the difference in the following ways:-

a. (-3.2t + 2.8) - (-5.1t + 7.8)

b. 1.9t - 5

c. (-3.2t + 2.8) - (-5.1t + 7.8)

Step-by-step explanation:

Commutative simply has to do with "moving around". In the case of addition, the commutative property rule is "x + y = y + x". When it comes to numbers, it my 7 + 8 = 8 + 7. In the case of multiplication, the commutative property rule is "m × n = n × m". So whenever commutative property is referred to, what is expected is "to move around". Commutative property rule can be executed as you pair, add or subtract like terms e.g 2a - 4 + 9a can be rewritten as 2a + 9a - 4 or 11a - 4

In the question, we were asked to subtract (7.8 - 5.1t) from (2.8 - 3.2t) and use the commutative property to show the difference in another way.

Subtracting (7.8 - 5.1t) from (2.8 - 3.2t) will give:-

(2.8 - 3.2t) - (7.8 - 5.1t) (This is the original expression)

Removing the bracket:

2.8 - 3.2t - 7.8 + 5.1t

= 5.1t - 3.2t + 2.8 - 7.8 (we have now shown the difference in another way)

Subtracting the like terms, will give: 1.9t - 5 (This is also the difference shown in another way).

Recall that the initial expression was

(2.8 - 3.2t) - (7.8 - 5.1t).

We can also use the commutative property rule to show the difference in the following way:-

(-3.2t + 2.8) - (-5.1t + 7.8)

By so doing, the figures have been rearranged without altering or affecting the outcome of the expression.

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A = 6
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2 years ago

Read 2 more answers

A department store has daily mean sales of $28,372.72. The standard deviation of sales is $2000. On Tuesday, the store sold

DiKsa [7]

Answer:

Tuesday z-score was 3.26.

Tuesday was a significantly good day.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A score is said to be significantly high if it has a z-score higher than 1.64, that is, it is at least in the 95th percentile.

In this problem, we have that:

$\mu = 28372.72, \sigma = 2000$

On Tuesday, the store sold $34,885.21 worth of goods. Find Tuesday's z-score.

This is Z when $X = 34885.21$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{34885.21 - 28372.72}{2000}$

$Z = 3.26$

Tuesday z-score was 3.26.

Was Tuesday a significantly good day?

A z-score of 3.26 has a pvalue of 0.9994. So only 1-0.9994 = 0.0006 = 0.06% of the day are better than Tuesday.

So yes, Tuesday was a significantly good day.

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Answer:

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Step-by-step explanation:

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