Notice that
so the constraint is a set of two lines,
and only the first line passes through the first quadrant.
The distance between any point 
in the plane is 
, but we know that 
and 
share the same critical points, so we need only worry about minimizing 
. The Lagrangian for this problem is then
with partial derivatives (set equal to 0)
We have
which tells us that
so that 
is a critical point. The Hessian for the target function is
which is positive definite for all 
, so the critical point is the site of a minimum. The minimum distance itself (which we don't seem to care about for this problem, but we might as well state it) is 
.
Answer:
Which graph is the result of reflecting f(x) = One-fourth(8)x across the y-axis and then across the x-axis?
On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and incresaes into quadrant 1. It goes through the y-axis at (0, 0.25) and goes through (1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 1 and increases in quadrant 2. It crosses the y-axis at (0, 0.25) and goes through (negative 1, 2).
On a coordinate plane, an exponential function approaches y = 0 in quadrant 3 and decreases into quadrant 4. It crosses the y-axis at (0, negative 0.25) and goes through (1, negative 2).
On a coordinate plane, an exponential funtion increases in quadrant 3 into quadrant 4 and approaches y = 0. It goes through (negative 1, negative 2) and crosses the y-axis at (0, negative 0.25).
Step-by-step explanation:
Answer:
11 over 13
Step-by-step explanation:
first, you deal with multiplication;
x = -12 + 14 - 12x + 13
second, deal with addition;
x = -2 - 12x + 13
third, take -12 to the other side then the negative changes to positive;
12x + x = -2 + 13
fourth, add them then simplify;
13x = 11
ans is 11 over 13
7 MPH because 2 1/3
in 20 minutes. So you multiply 20 by 3 you get 60. Then you multiply 2 by 3 you get 6. Then you multiply 1/3 x 3 and you get 1. 6=1=7 Hope This Helps
