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sattari [20]
2 years ago
6

Use the given data to find the equation of the regression line. Round the final values to three significant digits, if necessary

. Two different tests are designed to measure employee productivity and dexterity. Several employees are randomly selected and tested with these results.
Productivity 23 25 28 21 21 25 26 30 34 36

Dexterity 49 53 59 42 47 53 55 63 67 75

Mathematics
1 answer:
uysha [10]2 years ago
4 0

Answer:

The equation of the regression line is: y=5.055 + 1.905 \cdot x

Step-by-step explanation:

We have the following data:

\begin{array}{c|cccccccccc}Productivity&23&25&28&21&21&25&26&30&34&36\\Dexterity&49&53&59&42&47&53&55&63&67&75\end{array}

We can use the Least Squares Regression to find the line of best fit for a set of paired data.

To find the line of best fit for <em>n</em> points:

Step 1: For each (x,y) point calculate x^2 and xy.

Step 2: Sum all x, y, x^2 and xy, which gives us Σx, Σy, \sum x^2 and Σxy.

Step 3: Calculate Slope b:

b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}

where <em>n</em> is the number of points.

Step 4: Calculate Intercept a:

a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2}

Step 5: Assemble the equation of a line

y=a + b \cdot x

Following the above steps we get:

Step 1: Find x^2 and xy as it was done in the table

Step 2: Find the sum of every column:

\sum{X} = 269 ~,~ \sum{Y} = 563 ~,~ \sum{X \cdot Y} = 15596 ~,~ \sum{X^2} = 7473

Step 3: Use the following equations to find a and b:

a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 563 \cdot 7473 - 269 \cdot 15596}{ 10 \cdot 7473 - 269^2} \approx 5.055

b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 10 \cdot 15596 - 269 \cdot 563 }{ 10 \cdot 7473 - \left( 269 \right)^2} \approx 1.905\end{aligned}

Step 4: Assemble the equation of a line

y=5.055 + 1.905 \cdot x

The graph of the regression line is:

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1.) y=3
2.) y=13
     2y + y = 3y , 22+17= 39
     3y = 39 , divide 3 on each side (which cancels out the 3 with the y which leaves you with y)
3.) y=10
     3y - y = 2y , 35-15= 20
     2y=20 , do the same as # 2.
4.) y=4
     9y - 5y = 4y , 48-32= 16
     4y=16, do the same as #2 & #3
5.) (4,5)
     x + 3y = 19
   2x - 3y = -7
    solve for x first ; x + 2x= 3x , 19-7 = 12; 3x = 12 ; divide 3 ; x= 4. You know have to make the x's cancel out. so I will multiply -2 on the first equation. -2(x+3y=19)
     -2x - 6y = -38
      2x - 3y = -7
    Now solve for y ; -6y + -3y = -9y , -38 + -7 = -45; -9y=-45 ; divide by -9 (since they are both negative your answer will be positive) ; y= 5
6.) (6,8)
   x + 4y = 38
  -x - 3y = -30
solve for y first ; 4y - 3y = y , 38-30 = 8; y=8 (that simple!) Now you need to find a common multiple for 4 & 3 which is 12. So you will have to multiply each equation by either 4 or 3.
  (x + 4y = 38)*3      =     3x + 12y = 114         
 (-x - 3y = -30)*4     =     -4x - 12y = -120
solve for x ; 3x - 4x = -x , 114-120= -6 ; -x=-6. Since the x has a negative that means there's still a 1 there so -1x=-6 ; you will need to divide this which makes the 6 a positive; x=6


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