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Troyanec [42]
2 years ago
3

The number of calories needed in a daily diet varies directly as the weight of an individual. If 1,050 calories should be consum

ed daily for a 105-pound person, what is the weight of an individual who consumes 1,370 calories per day?
Mathematics
1 answer:
Anton [14]2 years ago
4 0

Answer:

The weight of an individual who consumes 1,370 calories per day is<u> 137 pound.</u>

Step-by-step explanation:

Given:

1,050 calories should be consumed daily for a 105-pound person.

Now, to get the weight of an individual who consumes 1,370 calories per day.

If 1,050 calories should be consumed per day for = 105-pound person.

So, 1 calorie should be consumed per day for    =105\div 1050

                                                                               =\frac{1}{10}

Then, 1,370 calories consumed per day for weight of =1,370\times \frac{1}{10}

=137\ pound.

Therefore, the weight of an individual who consumes 1,370 calories per day is 137 pound.

                                                   

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A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (80
miskamm [114]

Answer:

\epsilon = 3.958\times 10^{-3}

Step-by-step explanation:

The Young's Module of Aluminium is E = 69\times 10^{9}\,Pa. The axial stress on the specimen is:

\sigma = \frac{F}{A_{t}}

\sigma = \frac{35500\,N}{(0.01\,m)\cdot (0.013\,m)}

\sigma = 2.731\times 10^{8}\,Pa

The strain is derived of following expression:

\epsilon = \frac{\sigma}{E}

\epsilon = \frac{2.731\times 10^{8}\,Pa}{69\times 10^{9}\,Pa}

\epsilon = 3.958\times 10^{-3}

4 0
2 years ago
Help please !!!! It’s geometry
qaws [65]
The answer is true because if you multiply 3•(3) is will give you 9 and if you multiply 10•(3) it will give you 30 which gives you both of the sides for the larger one
7 0
2 years ago
which are the roots of the quadratic function f(b) = b2 – 75? check all that apply. b = 5 square root of 3 b = -5 square root of
malfutka [58]
<span>The answers are b = 5 square root of 3; b = -5 square root of 3. f(b) = b^2 – 75. If f(b) = 0, then b^2 – 75 ) 0. b^2 = 75. b = √75. b = √(25 * 3). b = √25 * √3. b = √(5^2) * √3. Since √x is either -x or x, then √25 = √(5^2) is either -5 or 5. Therefore. b = -5√3 or b = 5√3.</span>
8 0
2 years ago
Read 2 more answers
The graph shows a line and two similar triangles. On a coordinate plane, a line goes through (0, 0) and (8, 2). A small triangle
drek231 [11]

Answer:

  \dfrac{y}{x}=\dfrac{1}{4}

Step-by-step explanation:

When the line goes through the origin (0, 0), we can say that y is proportional to x. Then the ratio of y (the vertical measure) to x (the horizontal measure) is the same as the ratio of "rise" (the vertical change) to "run" (the horizontal change).

  y/x = rise/run = 1/4

The equation of the line is ...

  y/x = 1/4

4 0
2 years ago
Read 2 more answers
A patrolman spends 25% every day completing paperwork. The patrolman’s shift each day is 8 hours. How much of his time does he s
fredd [130]
Assuming the man works 8 hours straight without breaks:

25% is the same as 1/4 of something.

So, we just have to figure out what 1/4 (one quarter) of 8 equals.

You can think of it as a pizza cut into 8 slices. One slice is equivalent to one hour for the patrolman.

If we take away 1/2 (half) of the pizza, we have 4 slices, right? Since we start with 8 slices, half of that equals 4 slices. In other words, 50% (half) of the pizza = 4 slices.

Now, 25% (one quarter) of the pizza will equal half of what is left:

If we know that 50%=4 slices (or 4 hours), then 25% must be 2 slices (or 2 hours).

That's it! 25% of 8 hours = 2 hours.

***So, the patrolman spends 2 hours each day completing paperwork.***

Lets check our work:
We know 8 hours (or 8 slices)= 100%
(We know this because
8 slices = 1 whole pizza, or 100% of a pizza. Similarly,
8 hours = 1 whole shift or 100% of the man's shift ).

So

25% + 25% + 25% + 25% = 100%

If 100% of the mans shift = 8 hours:

2+2+2+2 = 8

It checks out!


Hope this helps!



4 0
2 years ago
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