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2 years ago

12

The average of five weights is 13 grams. This set of of five weights is then increased by another weight of 7 grams. What is the

average of the 6 weights?

1 answer:

Anastaziya [24]2 years ago

3 0

Answer:

12

Step-by-step explanation:

You just find the total weight and divide it by the number of weights

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The domain for f(x) and g(x) is the set of all real numbers. Let f(x) = 3x + 5 and g(x) = x2. Find g(x) − f(x).

kifflom [539]

Answer:

3x^2 + 8

Step-by-step explanation:

Given functions,

f(x) = 3x + 8 ----(1)

g(x) = x^2 -----(2)

Since,

(fog)(x) = f( g(x) ) ( Composition of functions )

=f(x^2) ( From equation (2) )

=3x^2 + 8 ( From equation (1) )

Hence,

(fog)(x)=3x^2 + 8

Step-by-step explanation:

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2 years ago

The exhaust system of an automobile is first given an emission check and then given a vibration check. The result of an emission

Andre45 [30]

Answer:

Step-by-step explanation:

The sample space is known to be the set of all possible outcomes of an experiment we cannot predict its outcome while the event space showcases the subset of the sample space, this may be a collection of outcomes of a random experiment.

From the given information:

The sample space = {SH, SL, SN, MH, ML, MN,UH, UL, UN}

The event that the emissions check is satisfactory = {SH, SL, SN}

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1 year ago

Given: Quadrilateral ABCD is a kite.

Leni [432]

Answer:

Step-by-step explanation:

One

The definition of a kite.

Two

Perpendicular. The diagonals meet at right angles

Three

I don't know if the term is still used, but when I first learned this material (many years ago) we called it the reflexive property.

Four

You found out that <AED = <CED which established that both are right angles. The problem is, you do not have enough information to prove SAS.

AAS is never a dependable reason for proving anything conguent.

HL is really your only choice.

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2 years ago

Read 2 more answers

A sample of 1714 cultures from individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiot

Damm [24]

Answer:

a) $p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

b) $\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

c) We are confident (95%) that the true proportion of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic is between 54.5% to 59.1%.

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

Description in words of the parameter p

$p$ represent the real population proportion of people who showed partial or complete resistance to the antibiotic

$\hat p$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

n=1714 is the sample size required

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part b

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{973}{1714}=0.568$ represent the estimated proportion of people who showed partial or complete resistance to the antibiotic

Part c

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.568 - 1.96 \sqrt{\frac{0.568(1-0.568)}{1714}}=0.545$

$0.568 + 1.96 \sqrt{\frac{0.56(1-0.56)}{1714}}=0.591$

And the 95% confidence interval would be given (0.545;0.591).

We are confident that about 54.5% to 59.1% of individuals in Florida diagnosed with a strep infection was tested for resistance to the antibiotic penicillin present partial or complete resistance to the antibiotic.

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2 years ago

Two buildings on level ground are 120 m and 85 m tall respectively. given that the angle of elevation of the top of the taller b

Luda [366]

Answer:

(-8,-5)

Step-by-step explanation:

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2 years ago