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SashulF [63]
2 years ago
14

Consider a tree T storing 100,000 entries. What is the worst-case height of T in the following cases?

Mathematics
1 answer:
Darina [25.2K]2 years ago
6 0

Answer:

Step-by-step explanation:

a.) The worst-case height of an AVL tree or red-black tree with 100,000 entries is 2 log 100, 000.

b.) A (2, 4) tree storing these same number of entries would have a worst-case height of log 100, 000.

c.) A red-black tree with 100,000 entries is 2 log 100, 000

d.) The worst-case height of T is 100,000.

e.)  A binary search tree storing such a set would have a worst-case height of 100,000.

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Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
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Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(c) The standard deviation of  test A is 80.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

50A=40B+50

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

A=40B+50\\=(40\times21)+50\\=890

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2>A=40B+50\\=(40\times29)+50\\=1210</h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2>A=40B+50\\=(40\times2)\\=80</h2>

Thus, the standard deviation of  test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

A=40B+50\\=(40\times28)+50\\=1170

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

A=40B+50\\=(40\times26)+50\\=1090

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

A=40B+50\\=(40\times6)+50\\=290

Thus, the value of IQR for test A is 290.

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58%

Step-by-step explanation:

We need to find what percent 290 is of 500.

percent = part/whole × 100%

percent = 290/500 × 100%

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If AB is parallel to CD and the slope of CD is -5, what sis the slope of AB?
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