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STatiana [176]
2 years ago
7

4. An airplane is traveling at a speed of 724 km/hr at a direction of 30 degrees. The wind is blowing from the west at 32 km/hr.

Find the resultant speed and true course of the plane.
Mathematics
1 answer:
tankabanditka [31]2 years ago
8 0

Answer:

28.8 degrees bearing above from the east.

Step-by-step explanation:

Given :

Direction =30 degrees

Speed =724 km/hr

Suppose x1, y1 be the velocity bearing in the east at the 30 degree

so x1 velocity = 724 cos 30 degree

y1 velocity = 724 sin 30  degree

As mention in the question the wind speed adding another 32 to the x1 speed.

Hence the resultant speed  is

velx1= 659\\vely1 = 362

The \ speed\  is\ determined \ by \ following\ formula\ \\ \sqrt{vel y1^2+ velx1^2} \\= \sqrt{659^2+362^2}\\=751.9 km/hr\\therefore\  \ the\  direction is\  arctan \\= vely1/ velx1 \\= arctan( 362/659) \ =28.8\  degrees\ above\ from\  the\  east

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