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Elina [12.6K]
1 year ago
6

a right circular cone has a height of 18 and a base radius of 12. A slice parallel to the base in made completely throught the c

one, and the resulting smaller cone has a volume that is 1/2 the volume of the original cone. What is the height of the smaller cone?
Mathematics
1 answer:
Scrat [10]1 year ago
8 0
<h2>Height of smaller cone is 14.29</h2>

Step-by-step explanation:

\texttt{Volume of cone, V = }\frac{1}{3}\pi r^2h

For the first cone

            Height, h = 18

            Radius, r = 12

Substituting

           \texttt{Volume of cone, V = }\frac{1}{3}\pi r^2h\\\\\texttt{Volume of cone, V = }\frac{1}{3}\times \pi \times 12^2\times 18=2714.34

Volume of new cone formed is half of the older cone.

Volume of new cone = 0.5 x 2714.34 = 1357.17

For the cone as the height reduces to 18 radius reduces to zero.

               tan\theta =\frac{12}{18}\\\\\theta =33.7^0

  \texttt{Volume of new cone = }\frac{1}{3}\pi r_1^2h_1\\\\tan\theta =\frac{r_1}{h_1}\Rightarrow r_1=h_1tan\theta\Rightarrow r_1=h_1tan33.7=0.667h_1\\\\\texttt{Volume of new cone = }\frac{1}{3}\pi \times (0.667h_1)^2h_1=0.467h_1^3

We have

              0.467h₁³ = 1357.17

                       h₁ = 14.29

Height of smaller cone = 14.29

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Step-by-step explanation:

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Area of Triangle = 0.5 * base * height

Base is 12 units

Height is 7 units, so

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Now,

Area of Rectangle = length * height

Length is 7

Height is 4

Area of Rectangle = 7 * 4 = 28

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kiruha [24]

Answer:

[1,\infty)

Step-by-step explanation:

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So we can plug anything for function a and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find (b \circ a)(x) and simplify now.

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Let's solve this to find the domain of (b \circ a)(x).

3x-3 \ge 0

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3x \ge 3

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x \ge 1

So we want x to be a number greater than or equal to 1.

The option that says this is [1,\infty)

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

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So a(-2)=3(-2)+1=-6+1=-5 and b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}.

Give an example why option B fails:

A number in the given set is 0.

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b(x)=\sqrt{x-4}

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Give an example why option D fails:

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A number not in the given set that works is 3.

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So a(3)=3(3)+1=9+1=10 and b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}.

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Required

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This implies that, a cone with base radius D is generated.

Recall that D = 17.

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