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2 years ago

_____ have larger blind spots and longer stopping distances compared to other vehicles.

Mathematics

2 answers:

maria [59]2 years ago

5 0

Answer:

D. Vans and Trucks

Step-by-step explanation:

Vans and trucks have larger blind spots and longer stopping distances compared to other vehicles because they are larger in size and it takes more time for them to stop.

Shalnov [3]2 years ago

5 0

Answer:

D. Vans and trucks

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On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter

andrezito [222]

Answer:

1) The common ratio = 1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio = 1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

3 0

2 years ago

Mark and his friends order two pizzas of the same size the first pizza is cut into 6 slices of equal size the second pizza is cu

Anettt [7]

Answer:

The first pizza is 6 slices, so each slice is 1/6 of a pizza. The second pizza is 4 slices, so each slice is 1/4 of a pizza. If you were to take one slice of each, you would get 1/6 +1/4 slice, which would be 5/12 of a pizza, as opposed to if you took 2 slices of the first pizza, which would only be 4/12 of a pizza.

3 0

2 years ago

True or False; In spherical geometry, there is only one equilateral triangle.

Elodia [21]

It's true. It must equal 180 degrees and the only way to accomplish that while it being an equilateral triangle is by having only one triangle! :)

3 0

2 years ago

El producto de dos números consecutivos es 552 cuáles son esos números?

lara31 [8.8K]

Answer: 23 y 24 ( ó -23 y -24)

Step-by-step explanation:

Dos números consecutivos se escriben como:

n y (n + 1)

done n es un numero entero.

Entonces "El producto de dos números consecutivos es 552"

Se escribe como:

n*(n + 1) = 552

n^2 + n = 552

n^2 + n - 552 = 0

Tenemos una cuadrática, las posibles soluciones son obtenidas con la formula de Bhaskara.

$n = \frac{-1 +- \sqrt{1^2 - 4*1*(-552)} }{2} = \frac{-1 +- 47}{2}$

Las dos soluciones son.

n = (-1 - 47)/2 = -48/2 = -24

n = (-1 + 47)/2 = 46/2 = 23

Si tomamos la primer solución, n = -24

Entonces los dos números consecutivos son:

n = -24

(n + 1) = -23

Si n = 23 entonces

n + 1 = 24

Lo cual tiene sentido, por que lo único que cambia son los signos, los cuales se cancelarían en la multiplicación.

7 0

2 years ago

For a certain type of copper wire, it is knownthat, on the average, 1.5 flaws occur per millimeter.Assuming that the number of f

mario62 [17]

Answer:

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 1.1156 occur / millimeters

Step-by-step explanation:

Step 1:-

Given data A copper wire, it is known that, on the average, 1.5 flaws occur per millimeter.

by Poisson random variable given that λ = 1.5 flaws/millimeter

Poisson distribution $P(X= r) = \frac{e^{-\alpha } \alpha ^{r} }{r!}$

Step 2:-

The probability that no flaws occur in a certain portion of wire

$P(X= 0) = \frac{e^{-1.5 } \(1.5) ^{0} }{0!}$

On simplification we get

P(x=0) = 0.223 flaws occur / millimeters

Conclusion:-

The probability that no flaws occur in a certain portion of wire of length 5 millimeters = 5 X P(X=0) = 5X 0.223 = 1.1156 occur / millimeters

5 0

2 years ago