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vovikov84 [41]
2 years ago
7

Honeycutt Co. is comparing two different capital structures. Plan I would result in 12,700 shares of stock and $109,250 in debt.

Plan II would result in 9,800 shares of stock and $247,000 in debt. The interest rate on the debt is 10 percent. The all-equity plan would result in 15,000 shares of stock outstanding. Ignore taxes for this problem.a. What is the price per share of equity under Plan I? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.)b. What is the price per share of equity under Plan II? (Do not round intermediate calculations and round your answer to 2 decimal places, e.g., 32.16.)
Business
1 answer:
Ulleksa [173]2 years ago
5 0

Answer:

Check the following calculations

Explanation:

All-Equity Plan:

Number of shares = 15,000

Plan I:

Number of shares = 12,700

Value of debt = $109,250

Price per share = Value of debt / (Number of shares under All-Equity Plan - Number of shares under Plan I)

Price per share = $109,250 / (15,000 - 12,700)

Price per share = $109,250 / 2,300

Price per share = $47.50

Plan II:

Number of shares = 9,800

Value of debt = $247,000

Price per share = Value of debt / (Number of shares under All-Equity Plan - Number of shares under Plan II)

Price per share = $247,000 / (15,000 - 9,800)

Price per share = $247,000 / 5,200

Price per share = $47.50

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A is f(x)= 1.5(x)

B: Find a graphing calculator to graph it.  (i.e. Desmos Graphing Calculator)

c:  The domain and range are both negative infinity to positive infinity.

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2 years ago
Return to Problem Navigation Morgan Company uses the perpetual inventory system and the gross method of recording sales discount
Ghella [55]

Amount to be recorded for accounts receivable would be $15000.

<u>Explanation:</u>

Accounts receivable are lawfully enforceable cases for installment held by a business for products provided as well as administrations rendered that clients/customers have requested yet not paid for. These are for the most part as solicitations raised by a business and conveyed to the client for installment inside a concurred time span.

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2 years ago
A flexible budget for 15,000 hours revealed variable manufacturing overhead of $90,000 and fixed manufacturing overhead of $120,
Ket [755]

Answer:

B. $270,000.

Explanation:

The computation of the total overhead cost is shown below:

But before that first we have to find out the variable overhead per hour which is

= $90,000 ÷ 15,000

= $6 per hour

Now

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= $6 per hour × 25,000

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So,

Total overhead cost is  

= Variable overhead for 25,000 hours + Fixed overhead cost

= $150,000 + $120,000

= $270,000

hence, the correct option is B. $270,000

6 0
1 year ago
The number of taxicabs in Motorville and the taxicab fares are regulated. The fare currently charged is Rs.500 a ride. Motorvill
larisa86 [58]

Answer:

The answer is below

Explanation:

i) The price elasticity of demand is given by the formula:

Price \ elasticity\ of \ demand=\frac{\Delta Q}{\Delta P} =\frac{\frac{Q_2-Q_1}{(Q_2+Q_1)/2} }{\frac{P_2-P_1}{(P_2+P_1)/2} } \\\\Price \ elasticity\ of \ demand=\frac{\frac{40-80}{(40+80)/2} }{\frac{600-500}{(600+500)/2} }=\frac{-2/3}{2/11} =3.667 (ignore \ the\ sign)

Since the price elasticity of demand is greater than 1 hence it is elastic

ii) Since the price elasticity of demand is elastic as a result of increase in fare, hence the total revenue would decrease.

iii)

Price \ elasticity\ of \ demand=\frac{\Delta Q}{\Delta P} =\frac{\frac{Q_2-Q_1}{(Q_2+Q_1)/2} }{\frac{P_2-P_1}{(P_2+P_1)/2} } \\\\Price \ elasticity\ of \ demand=\frac{\frac{120-80}{(120+80)/2} }{\frac{400-500}{(400+500)/2} }=\frac{0.4}{-2/9} =1.8 (ignore \ the\ sign)

Since the price elasticity of demand is greater than 1 hence it is elastic

4 0
2 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

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2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

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As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
2 years ago
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