2 years ago

Several workers have been injured from slip-and-fall hazards. What can a business do to reduce these injuries?

Health

2 answers:

Tanya [424]2 years ago

3 0

Answer:

Eliminate activities for all workers who are at risk for falling.

Explanation:

just took the test !

KiRa [710]2 years ago

3 0

Answer:

Explanation:

On Edge

You might be interested in

Which step did Woo Jin get wrong and why

denpristay [2]

Step 2 I think. Because some First Aid stuff needs to be done by the professionals.

7 0

2 years ago

Read 2 more answers

Cody Roberts weighs 190 lbs (86 kg). He has joined a local running club and wants to start carbohydrate loading 1-3 days prior t

Snowcat [4.5K]

Increasing muscle glycogen stores will need carbohydrate loading of 8-12g.kg/day, which may contribute 70-85% of total energy intake. Athletes or physically active individual may use carbohydrate loading as to gain endurance prior to competition. Thus, helping Cody Roberts to have better performance by sustaining in the race.

3 0

2 years ago

James sitting at his desk on the ground floor of an office building when the entire room starts shaking. Which action is most ap

Pepsi [2]

Answer:

Move under his desk.

Explanation:

if objects were to fall from above he would not be harmed

4 0

2 years ago

Read 2 more answers

Increased metabolic rate due to exercise is helpful because __________. A. the body uses more calories for everyday activities B

Alekssandra [29.7K]

Answer:

B. Toxins are removed from the body more quickly

3 0

2 years ago

Read 2 more answers

Prove sinA*cos2A=1/4sin4A*secA<br>

kolezko [41]

Answer:

The prove is below

Explanation:

From trigonometric identities:

$cos2A=cos(A+A)=cos^2A-sin^2A\\sin2A=sin(A+A)=2sinAcosA\\sin4A=sin(2A+2A)=2sin2Acos2A=2(2sinAcosA)(cos^2A-sin^2A)=4sinAcos^3A-4cosAsin^3A\\secA=\frac{1}{cosA}$

Therefore:

$\frac{1}{4}sin4AsecA = \frac{1}{4}( 4sinAcos^3A-4cosAsin^3A)\frac{1}{cosA}\\= sinAcos^3A-cosAsin^3A(\frac{1}{cosA} )\\=sinAcos^2-sin^3A\\=sinA(cos^2A-sin^2A)\\But\ cos^2A-sin^2A=cos2A\\Therefore:sinA(cos^2A-sin^2A)=sinAcos2A\\\frac{1}{4}sin^4Acos2A=sinAcos2A$

4 0

2 years ago