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Feliz [49]
2 years ago
12

PLEASE ANSWER ASAP AND EXPLAIN!!!!!!!!!!!

Mathematics
1 answer:
MrRissso [65]2 years ago
6 0

Answer: use mathpapa

Step-by-step explanation:

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Chris has a large collection of hockey cards and wants to get rid of some of his hockey cards he gives 2 cars away on day 1,4 ca
Marizza181 [45]

Answer:

I'm not sure for which answer you're asking for so I'll give you all of them.  On the tenth day, Chris will give away 1024 cards.

Step-by-step explanation:

On the fourth day he will give away 16, on the fifth day 32, on the sixth day 64, on the seventh say 132, on the eighth day 264, on the ninth day 528, and on the tenth day 1024

6 0
2 years ago
32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t
Lorico [155]

Answer:

A.  21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly​ two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2  * 68%^8 = 0.21066= 21.06%

(b) more than​ two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10   +   1P10 * P(yes)^1 * P(no)^9   +  2P10 * P(yes)^2 * P(no)^8  =

10!/0!10!* 32%^0  * 68%^10    +   10!/1!9!* 32%^1  * 68%^9   +   10!/2!8!* 32%^2  * 68%^8

0.02113 + 0.09947 + 0.21066  =  0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and​ five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2  * 68%^8    +   10!/3!7!* 32%^3  * 68%^7   +   10!/4!6!* 32%^4  * 68%^6  +  10!/5!5!* 32%^5  * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

8 0
2 years ago
Grades 3, 4, and 5 have their annual field day together. Each grade level is given 16 gallons of water.
sineoko [7]

Answer:

Their will be enough water for each student to consume 2 cups of water.

Step-by-step explanation:

Grade 3, 4 and 5 have their annual field day together . Each grade level is given 16 gallons of water. This means the three grades have 16 × 3 = 48 gallons of water.

The total students involved is 350 student. The total student is the sum of the student in all three grades.

Since the water will be distributed to the students in cups let us convert gallons to cups.

1 gallons = 16 cups

48 gallons = ? cups

cross multiply

48 × 16 = 768 cups.

768 cups of water is available to be shared among the 350 students.

1 student is entitled to 2 cups of water.

350 students will consume 350 × 2 = 700 cups of water.

Therefore, their will be enough water for each student to consume 2 cups of water.

6 0
2 years ago
Find the area! Its an irregular shape. Q attached, TY~Karma
Yuki888 [10]
Make it into 3 shapes
4 0
2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
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