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2 years ago

By the end of prophase, each of the following has occurred except ____.

Biology

1 answer:

Phantasy [73]2 years ago

3 0

Answer:

By the end of prophase, each of the following has occurred except <em>lining up of chromosomes in the cell.</em>

Explanation:

The lining up of the chromosomes in the cell occurs during the third stage of cell division. This stage is termed as the metaphase.

Prophase is the first stage of cell division. Hence, the lining of the chromosomes does not occur by the end of prophase.

During the prophase, the chromatin material condenses and become more compact so that the chromosomes become visible. The nucleolus and the nuclear envelope disappear by the end of prophase. Hence, all other options A, B and C occur by the end of prophase except option D.

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Given that the mean cuteness of the current herd is 39.7 OMGs, the BAF workers picked the 16 cutest adults and allow them to rep

hammer [34]

Answer: 41.5 OMGs is the predicted mean cuteness in the next generation.

Explanation:

Cuteness is a way to measure relative ability of individuals with a certain genotype to reproduce successfully.

Mean cuteness is given as the summation of individual cuteness. Mean cuteness also changes in the next generation.

The mean cuteness of the current herd was given as 39.7 OMGs and after 16 individuals were chosen, the mean was given as 41.5.

This implies that there was a change already as mean cuteness will either increase or decrease in the next generation after selection. Here, 39.7 increased to 41.5 .

The predicted mean cuteness is therefore 41.5 OMGs.

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2 years ago

Explain why the vessels that transport water in trees must be very small in diameter.

kipiarov [429]

Answer:

The diameter of the xylem vessels should be small in order for the capillary action to take place.

Explanation:

The vessels through which water is transported to different parts of the plants and trees are the xylem. Water is transported in the trees through a mechanism named as capillary action. This mechanism can occur only if the diameter of the vessels are small.

The water molecules adhere to the walls of xylem and an upward force is generated. If the diameter of the vessels i.e xylem would be small then the surface tension between the xylem and water molecules would be enough to move the water in an upward direction.

6 0

2 years ago

Grand Canyon is getting wider every day. What is making the canyon wider?

ira [324]

The Grand Canyon of Arizona is one of world’s largest and steepest canyons. It ranges up to 277 miles long and 18 miles wide. Its formation is carved due to the erosive power of the water’s current. As heavy rains continue to occur, more rocks and stones erode and fall which adds length and width to the Grand Canyon.

4 0

2 years ago

Read 2 more answers

state one reason why a glucose molecule is more likely than a sucrose molecule to diffuse through an artificial membrane

zimovet [89]

Answer:

A glucose molecule is smaller

Explanation:

An artificial membrane has pores of a specific size.

Molecules that are small enough can pass through the pores, but others may be too big.

Glucose (C₆H₁₂O₆) has a certain size, but a sucrose molecule (C₁₂H₂₂O₁₁) is bigger.

If the membrane pores are just the right size, a glucose molecule will be able to pass through, but a sucrose molecule won't.

8 0

2 years ago

Read 2 more answers

Thyroxine, an important hormone that controls the rate of metabolism in the body, can be isolated from the thyroid gland. If 0.4

MA_775_DIABLO [31]

Answer:

The molar mass of thyroxine is 18,2 g/m

Explanation:

To solve this we must apply the colligative property of cryoscopic descent whose formula is:

T° sv pure - T° sl = Kf x molality

So let's replace our values

5,444°C - 5,144°C = 5,12 °C/m x molality

0,3°C = 5,12 °C/m x molality

0,3°C / 5,12 m/°C = molality

2,5 m

Now you should know that molality is moles from solute in 1kg of solvent but you dont have 1kg you have just 10 g. Let's convert for the rule of three

10 g = 0'010 kg

If 1 kg has 2,5 moles of thyrosine, how many for 0,010 kg

moles = (0,010kg * 2,5 moles)/1kg

moles = 0,025

Now we have the moles of thyrosine in our solution and we were informed that we dissolved 0,455 g so let's get the molar mass (mass of compound for one mole)

moles = mass/ molar mass

molar mass = mass/moles

molar mass = 0,455g/0,025 moles

molar mass = 18,2 g/m

3 0

2 years ago