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telo118 [61]
2 years ago
11

Which of the following reflects Moore's law? Multiple Choice The doubling of computer chip performance per dollar every two year

s. A company's ability to acquire small amounts of MIS equipment for cheaper cost. A company's ability to acquire small amounts of capital for spending on innovative ideas every two years The doubling of computer chip performance per dollar every six months.
Computers and Technology
1 answer:
Katena32 [7]2 years ago
4 0

Answer:

The correct answer is A.

Explanation:

Moore's Law states/predicts that the maximum number of transistors that can be used on integrated circuits (processors etc.) will be doubled every two years so it basically predicts an exponential growth in terms of transistors used.

Doubling the number of transistors used means that it will almost certainly increase the performance of the processors. Of course there are a lot of other variables that the performance depends on but Moore's Law is proven to be true and  is being used since 1960's. The answer given in option A is the one that best reflects on this law.

I hope this answer helps.

You might be interested in
The area of a square is stored in a double variable named area. write an expression whose value is length of the diagonal of the
cestrela7 [59]

Answer:

The correct answer to the following question will be "Math.sqrt(area*2)".

Explanation:

  • The Math.sqrt( ) method in JavaScript is used to find the squares root of the given figure provided to the feature as a variable.
  • Syntax Math.sqrt(value) Variables: this function takes a single variable value that represents the amount whose square root is to be determined.
  • The area of the figure is the number of squares needed to cover it entirely, like the tiles on the ground.

Area of the square = side times of the side.

Because each side of the square will be the same, the width of the square will only be one side.

Therefore, it would be the right answer.

5 0
2 years ago
Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
2 years ago
During the boot process, what does the processor do after the computer circuits receive power?
ZanzabumX [31]

Answer:

When ROM receives power, its ROM BIOS instructions are activated and they load the operating system into RAM. This startup sequence is referred to as the boot process. After the operating system is loaded, the computer can accept input, display output, run software, and access your data.

8 0
2 years ago
Assume a program requires the execution of 50 x 106 FP instructions, 110 x 106 INT instructions, 80 x 106 L/S instructions, and
Molodets [167]

Explanation:

FP - 50 \times 10^6

CPI - 1

INT -110 \times 10^6,

CPI - 1

I/S - 80 \times 10^6 ,

CPI - 4

Branch - 16 \times 10^6

CPI - 2

Clock Speed - 2 \times 10^9

Time(old) =\frac{50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)}{2 x 10^9}

Time(old) = 256 \times 10^ {-3}

Time(new) =  \frac{256 \times 10^{-3}}{2}

                = 128 \times 10^{-3}

                =\frac{CPI(new) x [50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)]}{2 x 10^9}

                =  128 \times 10^{-3}

CPI(new) = \frac{-206}{50}

               = -4.12

3 0
2 years ago
Write a destructor for the CarCounter class that outputs the following. End with newline.
ycow [4]

Answer:

Following are the code to this question:

CarCounter::~CarCounter()//Defining destructor CarCounter

{

cout << "Destroying CarCounter\n";//print message Destroying CarCounter

}

Explanation:

Following are the full program to this question:

#include <iostream>//Defining header file

using namespace std;

class CarCounter //Defining class CarCounter

{

public:

CarCounter();//Defining constructor CarCounter

~CarCounter();//Defining destructor CarCounter

private:

int carCount;//Defining integer variable carCount

};

CarCounter::CarCounter()//declaring constructor  

{

carCount = 0;//assign value in carCount variable

return;//using return keyword

}

CarCounter::~CarCounter()//Defining destructor CarCounter

{

cout << "Destroying CarCounter\n";//print message Destroying CarCounter

}

int main() //Defining main method

{

CarCounter* parkingLot = new CarCounter();//Defining class object parkingLot

delete parkingLot;//

return 0;

}

  • In the given C++ language code, a class "CarCounter" is defined, and inside the class, a "constructor, Destructors, and an integer variable" is defined.  
  • Outside the class, the scope resolution operator is used to define the constructor and assign value "0" in the integer variable.  
  • In the above-given code, the scope resolution operator, to define destructor and inside this cout function is used, which prints a message.  
  • In the main method, the class object is created, which automatically calls its class constructor and destructors.  
7 0
2 years ago
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