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Oksi-84 [34.3K]
2 years ago
7

Ishmael would like to capture a selected portion of his screen and then capture actions he preforms on that selected portion. Wh

at should he do? Use the video from my pc command use the insert screen recording control create poster frame use embed code
Computers and Technology
1 answer:
kompoz [17]2 years ago
5 0

Answer:

Use the Insert Screen .

Explanation:

Remember, on most computer keyboard you'll find a button named "Insert Screen' which functions as a screenshot too. Also, note that if Ishmael is using Windows operating system he should simply do the following;

1. open the window you want to screenshot

2. click the Screenshot button

But to select a part of the screen he would need to use Screen Clipping which would allow him select the part of the window that he wants. ( It screen will look opaque)

3. the pointer would change to a cross, then he should press and hold the left mouse button and drag to select the part of the screen that he wants to capture.

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Does the Boolean expression count > 0 and total / count > 0 contain a potential error? If so, what is it?
Semenov [28]

<u>Answer:</u>

<em>Assuming that all the necessary declarations are made and given statements are only an extract, we can conclude that the given piece of code contains error. </em>

<u>Explanation:</u>

Let us analyze each one in order.

<em>count >0 </em> This statement is right if we match this with the <em>syntax of regular comparison operation</em>. Here count is an operand, “0” is the constant operand and these two operands are operated by the operator “>”.

when we take total / count >0 Here count>0 returns <em>Boolean and total is assumed to be an integer and an integer cannot be divided by a Boolean value. so it can be rectified as (total / count)>0. </em>

6 0
2 years ago
PLEASE HELP PROGRAMMING WILL GIVE BRAINLIEST
JulijaS [17]
The fourth choice is correct.
5 0
2 years ago
Writing in Java, write a program that prompts the user to input an integer and then outputs both the individual digits of the nu
larisa [96]

Answer:

//Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

       int in;

     //scanner class object to read the input

    Scanner scr=new Scanner(System.in);

     // variable to keep running total

    int total=0;

    System.out.println("please enter an Integer:");

     // read the input first time

    in=scr.nextInt();

    System.out.print("individual digits of "+in+" is ");

    if(in<0)

    {

        in=-(in);

    }

   

 

     //call the function to print the digits of number

   print_dig(in);

   System.out.println();

    //calculate the sum of all digits

   do{

       int r=in%10;

       total=total+r;

       in=in/10;

   }while(in>0);

    //print the sum

   System.out.println("total of digits is: "+total);

     

   }catch(Exception ex){

       return;}

}

 //recursive function to print the digits of number

public static void print_dig(int num)

{  

    if(num==0)

    return;

    else

    {

    print_dig(num/10);

    System.out.print(num%10+" ");

    }

}

}

Explanation:

Read a number with the help of object of scanner class.if the input is negative

then make it positive number before calling the function print_dig().call

the recursive method print_dig() with parameter "num".It will extract the digits

of the number and print then in the order. Then in the main method, calculate

sum of all the digits of number.

Output:

please enter an Integer:                                                                                                  

3456                                                                                                                      

individual digits of 3456 is 3 4 5 6                                                                                      

total of digits is: 18

please enter an Integer:                                                                                                  

-2345                                                                                                                      

individual digits of -2345 is 2 3 4 5                                                                                      

total of digits is: 14

6 0
2 years ago
Of 500 sessions that occurred on a website during a one-week period, 200 of them started on the homepage; 100 of these 200 sessi
Elena L [17]

Answer:

the homepage bounce rate

Explanation:

Bounce rate is defined as the percentage of people that visits a page on a website and then exit or leave. That is, the visitors did not view any other page except the first one and they just leave the page after that visit. In order to get the bounce rate, the total number of visitors to a single page is taken and its then divided by the total number of visits to the website. For example, if the total number of visitors to a website over a period of time is 3000, while those that only visited a page on the website is 500, then the bounce rate is

(500/3000) * 100 = 16%

For this question, the homepage recorded 100 visited only once out of 200 which means homepage bounce rate is 50% : (100/200)*100

While website bounce rate is total number of bounces across the website/total visit to the website

100+100 =200 this is the total bounces across the website

200/500 :500 is the total visit to the website

(200/500)*100 = 40 %

Therefore the homepage bounce rate is higher than the site bounce rate

7 0
2 years ago
What is the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz? Group of answer choices
denpristay [2]

Answer:

15.420 dB

Explanation:

the Gain (dB) of a transmission if the Maximum Data Rate is 1 Gbps and the Bandwidth =7000 MHz is 15.420 dB.

3 0
2 years ago
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