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Marrrta [24]
2 years ago
15

The nuclear membrane's role in the regulation of gene expression involves _____. The nuclear membrane's role in the regulation o

f gene expression involves _____. protein activation translation protein degradation regulating the transport of mRNA to the cytoplasm RNA processing
Biology
1 answer:
Gala2k [10]2 years ago
8 0

Answer:

regulating the transport of mRNA to the cytoplasm

Explanation:

In eukaryotes, the process of transcription occurs in the nucleus while ribosomes are present in the cytoplasm or on the surface of the rough endoplasmic reticulum. Therefore, the mRNA should leave the nucleus and enter the cytoplasm to serve in the process of protein synthesis. The nuclear envelope contains the nuclear pore complex (NPC). The nuclear pore complex includes several specific nucleoporins embedded in the nuclear envelope.

The NPC serves as the passageway for the transport of mRNA molecules to the cytoplasm. The mature mRNA binds to specific exporter proteins in the nucleus and forms ribonucleoprotein particles that are allowed to pass through the nuclear pore complex.

The middle and carboxyl domain of mRNA exporter binds to the phenylalanine-glycine (FG) repeats in FG nucleoporins to facilitate the mRNA transport. Therefore, the transport of mRNA from the nucleus to the cytoplasm is regulated by the nuclear pore complex. This is how the nuclear membrane is involved in the regulation of gene expression.

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The flesh-eating bacteria, vibrio vulnificus, destroys healthy tissue. infectious agents such as this are best classified as wha
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kmf Of the 40 specimens of bacteria in a dish,3 specimens have a certain trait. If 5 specimens are to be selected from the dish
almond37 [142]

Answer:

\frac{C^{3}_1* C^{47}_4}{C^{40}_5}

Explanation:

It is given that out of 40, total 5 specimen are selected.

Thus, the number of ways in which 5 specimens are selected from a given sample of 40 is given by

C^{40}_{5}\\

Number of specimen with certain trait is equal to 3.

Now, total 5 specimen are selected out of which one specimen is selected from the set of specimen that has certain trait (i.e out of 3) while the remaining four specimen will be selected from the rest 40-3=37 specimen.

Thus, the probability of choosing only 1 of the 5 specimens with the trait is equal to

\frac{C^{3}_1* C^{37}_4}{C^{40}_5}

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