The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
f swimmers to sign up in order to be cost effective. Last year’s data showed that during 8 swim sessions the average number of entry-level swimmers attending was 15. Suppose the instructor wants to conduct a hypothesis test and the alternative hypothesis is "the population mean is greater than 15" If the sample size is 5, σ is known, and alpha = .01, the critical value of z isA) 2.575B) -2.575C) 2.33D) -2.33E) 2.45
Given that the local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number of swimmers to sign up in order to be cost effective.
(Right tailed hypothesis test for population mean at 1% significance level)
Sample size = 8
Since this is one tailed, the critical value of Z for 100-1 = 99% would be
c) 2.33
It is positive because right tailed test, and it is 2.33 because cumulative prob of 2.33 under Z is 99%
There is no work. i just did it in my head. x = 15 because 15^2 equals 225 and 15+2 = 17 so if 15*15 equals 225 then if you add 30 more that is 255. 30 is equal 2*15 and so you could also say 15*15+(15*2) so 15*17 = 255 so x = 15. you're welcome.