Answer:
The answer is viruses
Explanation:
Because it is a harmful software hidden inside another and usually performs a harmful action, such as destroying data.
Answer: Even though the hardware is inexpensive the writing of program is not efficient through this method as proper development of program is necessary for the clear execution due to factors like:-
- The facility of writing program even the cost of hardware is less but it is not a free facility.
- It also has a slower processing for the execution of the program
- The construction of the efficient program is necessary for the compilation and execution of it rather than poorly constructed program is worthless and inefficient in working.
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
Answer:
- <em>Their country can support </em><u><em> 128 </em></u><em>unique license plates</em>
Explanation:
Since there is space for<em> 7 digits </em>on each <em>license plate</em>, the first plate starts at <em>0000000 </em>(seven 0).
<em>Binary numbers</em> contain only the digits 0 and 1.
Thus, there are only two possibilities for each digit.
Using the multiplication counting principle, the number of total different binary numbers, with seven digits is 2 multiplied seven times:
- 2 × 2 × 2 × 2 × 2 × 2 × 2 = 2⁷ = 128 ← answer
