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dusya [7]
2 years ago
7

Assume that securitization combined with borrowing and irrational exuberance in Hyperville have driven up the value of existing

financial securities at a geometric rate, specifically from $6 to $12 to $24 to $48 to $96 to $192 over a six-year time period. Over the same period, the value of the assets underlying the securities rose at an arithmetic rate from $6 to $9 to $12 to $15 to $18 to $21.
Instructions: Enter your answer as a whole number.

If these patterns hold for decreases as well as for increases, by how much would the value of the financial securities decline if the value of the underlying asset suddenly and unexpectedly fell by $12?
Business
1 answer:
jekas [21]2 years ago
5 0

Answer:

When the value of existing financial securities rose from $6 to $192, the value of underlying assets rose from $6 to $21. It is also known these patterns hold as much for increases as for decreases. Notice that the original value of both the existing financial securities and underlying assets is $6.

Explanation:

Now, there occurs a $12 fall in the underlying assets. This means the value of underlying assets falls from $21 to its original level of $9 (=$21 — $12), thereby causing the value of existing financial securities to also fall from $192 to its original level of $9. This means the value of the financial securities declines by $183 (= $192 — $9).

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what types of political, economic, and competitive challenges does MTV networks international face by operating worldwide?​
Marysya12 [62]

<u>Explanation:</u>

Remember, MTV is a cable TV company initially founded in the United States.

Political challenges:

There may be differences in administrative costs in each country of operations. For example, the manner and value of taxes paid in the USA may be different in another country like France.

Economic challenges:

The level of economic growth may affect the amount and number of people who spend on entertainment leading to a decline in revenue and an increased need for aggressive marketing campaigns.

Competitive challenges:

Each country may already have other cable TV companies that a percent of the market share and so this it becomes a challenge to compete with these domestic companies.

6 0
1 year ago
Build a schedule for the following staffing requirements, giving workers two consecutive days off per cycle (not including Sunda
jasenka [17]

Answer:

Explanation:

The following process is used to schedule staffing requirements.

Start appointing workers in a way that two days contain the lowest amount of staff required are designated first.

Then, we minus 1 from each cell except for the selected pair of days.

After that, we lookout for pairs of days that contain the least amount of staff requirements.

We will then repeat the above process until the staffing requirements are fully met.

OUTPUT:

\ A\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B\ \ \ \ \ \ \ \ \ \ \ C\ \ \ \ \ \ \ \ \ \ \ D\ \ \ \ \ \ \ \ \ \ \ E\ \ \ \ \ \ \ \ \ \ \ F\ \ \ \ \ \ \ \ \ \ \ G

1 \ \ \      \ Day \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Mon \ \ \ \ \ \ \ \ \ \ \  Tue \ \ \ \ \ \ \ \ \ \ \ Wed \ \ \ \ \ \ \ \ \ \ \  Thur \ \ \ \ \ \ \ \ \ \ \ Fri \ \ \ \ \ \ \ \ \ \ \ Sat

2 \ \ \      \ Staff \ needed  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5

3 \ \ \      \ Worker \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ \mathbf{2 \ \ \ \ \ \ \ \ \ \ \  3} \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5      

4 \ \ \      \ Worker \ 2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \mathbf{ 2 \ \ \ \ \ \ \ \ \ \ \  3} \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \ 4

5 \ \ \      \ Worker \ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ \ \mathbf{1 \ \ \ \ \ \ \ \ \ \ \  2} \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \ 3    

6 \ \ \      \ Worker \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \  2 \ \ \ \ \ \ \ \ \ \ \ \mathbf{1 \ \ \ \ \ \ \ \ \ \ \  2} \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ 2

7 \ \ \      \ Worker \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  1 \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \  2 \ \ \ \ \ \ \ \ \ \ \mathbf{0 \ \ \ \ \ \ \ \ \ \ \ 1}

8 \ \ \      \ Worker \ 6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  0 \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \  1 \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \ 1

9 \ \ \      \ No \ working^* \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \  4 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 5

10    *count the number of workers after excluding highlighted cells and 0 values.

Day      Minimum number of workers needed

Mon     \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \     3

Tue  \ \ \ \ \ \ \ \ \   \  \ \ \ \ \ \ \ 4

Wed  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2

Thur  \ \ \ \ \ \ \ \ \ \ \  \ \ \ 3

Fri  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4

Sat  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5

6 0
1 year ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
2 years ago
A tire manufacturer produces 400 tires valued at $20 each. Three hundred tires are sold to a tire shop, which then sells them to
Leto [7]

Answer: $17,000

Explanation:

Produced =400 x $20= $8000

Tire shop bought = 300 x$20 =$6000

Household bought =300 x$50 =$15000

Household - Tire shop = $15000 - $6000 =$9000

GDP= $9000+ $8000 =$17000

4 0
2 years ago
Which of the following factors does not affect the initial market price of a stock?
MissTica

Answer:

The correct answer is (C)

Explanation:

Generally the common stocks worth per share is normally a limited quantity, for example, $0.05 or $0.01 and it has no association with the market estimation of the price of stock. The standard worth is once in a while referred to as the regular stocks.  The par value has no connection with the price of the stock.

7 0
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