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Brums [2.3K]
2 years ago
12

Which of the following ordered pairs lies on the graph of h(x) = -2x²?

Mathematics
1 answer:
miv72 [106K]2 years ago
8 0

The order pair that lies on the graph of h(x) = -2(x^2) is (1, -2). By substituting the given ordered pair only (1, -2) will satisfy the equation.

 h(x) = -2(x^2)

  -2 = -2(1^2)

  -2= -2(1)

  -2= -2

So the ordered pair lies on the graph is (1, -2)

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Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
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\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
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center\ ({{ h}},{{ k}})\\
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\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
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<span>Let x = # of rides

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Answer:

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