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2 years ago

5

The equation d = d equals StartFraction m Over V EndFraction. can be used to calculate the density, d, of an object with mass, m

, and volume, V. Which is an equivalent equation solved for V?

2 answers:

Alisiya [41]2 years ago

6 0

Answer:

m/d = V

Step-by-step explanation:

Bad White [126]2 years ago

5 0

Answer:

m/d=V

Step-by-step explanation:

I did the quiz

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M2/n2 is equivalent to _____.

tankabanditka [31]

Answer:

$\frac{m^2}{n^2}$ is equivalent to $m^2 \cdot n^{-2}$

Step-by-step explanation:

Using exponent rules:

$a^{-n}=\frac{1}{a^n}$

Given the expression:

$\frac{m^2}{n^2}$

⇒ $\frac{m^2}{n^2} = m^2 \cdot \frac{1}{n^2}$

Apply the exponent rule, we have;

$m^2 \cdot n^{-2}$

Therefore, the given expression $\frac{m^2}{n^2}$ is equivalent to $m^2 \cdot n^{-2}$

8 0

2 years ago

If you are one of the first 100 people to join a new health club, you are charged a joining fee of $49. Otherwise, you are charg

Drupady [299]

Answer:

a) Total cost = 49 + 38.75m

b) Total cost = 149 + 38.75m

c) The graphs of the lines are parallel and both has slope of - 2.5

d)Difference in total cost = $132.5

Step-by-step explanation:

Total cost , TC = Initial membership fee + monthly charges

a) TC = 49 + 38.75m

b)TC = 149 + 38.75m

d) 149 + 38.75(6months) = 381.5

49 + 38.75(12months) = 514

Difference in total cost = 514 -381.5 = $132.5

7 0

2 years ago

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Ghella [55]

Answer: The required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

Step-by-step explanation: Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written $\frac{1}{4}$ as many articles as Mustafa has and Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper. Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$

And the solution of the above inequality is as follows :

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.$

Thus, the required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

4 0

2 years ago

Read 2 more answers

A taxi service charges a flat fee of $1.25 and $0.75 per mile. If Henri has $14.00, which of the following shows the number of m

MariettaO [177]

You want to get the total amount Henri has which is $14 then subtract the flat fee.
14-1.25=12.75, He has $12.75 left to pay for miles, Since the taxi charges .75 a mile, you get $12.75/.75= 17
Henri has enough to pay to ride 17 miles.

Hope this helps

5 0

2 years ago

Read 2 more answers

Translate to an algebraic expression n−1 increased by 110%

Anon25 [30]

Answer:

Part 1) The algebraic expression is equal to $1.10(n-1)$ or $1.10n-1.10$

Part 2) The algebraic expression is equal to $\frac{1.10}{n}$

Step-by-step explanation:

Part 1) Algebraic expression of (n-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

$1.10(n-1)$

Distributed

$1.10n-1.10$

Part 2) Algebraic expression of n^(-1) increased by 110%

we know that

110%=110/100=1.10

so

The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)

Remember that

$n^{-1}=\frac{1}{n}$

so

$1.10(n^{-1})=1.10\frac{1}{n}=\frac{1.10}{n}$

6 0

2 years ago