<span>It is false since the rational function is discontinuous when the denominator is zero. But the denominator is a polynomial and a polynomial has only finitely many zeros. So the discontinuity points of a rational function is finite. </span>
Answer:
the first and last one apply
Step-by-step explanation:
just did it on edu
Answer:
A) Yes, because P (F∩S) = 0
Step-by-step explanation:
Hello!
50 customers of a store were asked to choose between two discounts:
Discount 1: 20% off all purchases for the day.
Discount 2: 10% off all purchases for the week.
28 choose discount 1
22 choose discount 2
F: the selected person choose discount 1.
S: the selected person choose discount 2.
Two events are mutually exclusive when the occurrence of one of them prevents the other from occurring in one repetition of the trial and the intersection between these two events is void with zero probability of happening.
In this case, since the customers were asked to choose one out of the two events, if the customer chooses the first one, then he couldn't have chosen the second one and vice-versa. Then the intersection between these two events has zero probability, symbolically:
P(F∩S)=0
I hope it helps!
In 8 hours, every barber completed 24 haircuts which gave a product of 120. 24 divided by 8 is 3. The answer is 3 haircuts per hour.