answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pavlova-9 [17]
1 year ago
12

A heron is perched in a tree 50 feet above sea level. Directly below the heron, a pelican is flying 17 feet above sea level. Dir

ectly below the birds is a trout, swimming 23 feet below sea level.
Select all the statements that are true:
A. The difference in height between the pelican and the heron is -33 feet
B. The difference in height between the pelican and the heron is 33 feet
C. The distance between the heights of the pelican and heron is -33 feet
D. The difference in height between the pelican and the trout is -40 feet
E. The difference in height between the pelican and the trout is 40 feet
F. The distance between the heights of the pelican and the trout is 40 feet.
Mathematics
1 answer:
Elenna [48]1 year ago
4 0

Answer:

Only A, E, and F are correct.

Step-by-step explanation:

The difference between two points is P_1-P_2, thus the difference between the height of the Pelican and the height of the Heron is P_p-P_h = 17ft-50ft=-33ft, and between the Pelican and the trout it is P_p-P_t=17ft-(-23ft)=40ft.

The distance between two points is just the absolute value of the difference between them. Between the Pelican and the Heron it is|P_p-p_h|= 33ft, and the distance between the Pelican and the Trout is |P_p-P_t|=40ft.

Therefore,

A is correct;

B is incorrect (difference is not positive);

C is incorrect (distance cannot be negative);

D is incorrect (difference is not positive);

E is correct;

F is correct;

You might be interested in
The sum of two numbers is 90. The larger number is 14 more than 3 times the smaller number. Find the numbers
e-lub [12.9K]

Answer:

The numbers are 19 and 71.

Step-by-step explanation:

Let x and y represent the two numbers.  Then x + y = 90.  

Also, if we assume that the larger number is y, then y = 3x + 14.

We must solve this system of linear equations.  Since we already have the result of solution for y  (y = 3x + 14), let's use the substitution method to find the solution:

x + y = 90 becomes x + 3x + 14 = 90, or:

4x = 76.  Thus, x = 76/4, or 19.       If x = 19, then y = 3(19) + 14, or y = 71.

The numbers are 19 and 71.

Note that these add up to 90, as they must, and that 71 is 14 more than 3 times 19.

7 0
2 years ago
Two random samples are taken from private and public universities
kati45 [8]

Answer:

Step-by-step explanation:

For private Institutions,

n = 20

Mean, x1 = (43120 + 28190 + 34490 + 20893 + 42984 + 34750 + 44897 + 32198 + 18432 + 33981 + 29498 + 31980 + 22764 + 54190 + 37756 + 30129 + 33980 + 47909 + 32200 + 38120)/20 = 34623.05

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (43120 - 34623.05)^2+ (28190 - 34623.05)^2 + (34490 - 34623.05)^2 + (20893 - 34623.05)^2 + (42984 - 34623.05)^2 + (34750 - 34623.05)^2 + (44897 - 34623.05)^2 + (32198 - 34623.05)^2 + (18432 - 34623.05)^2 + (33981 - 34623.05)^2 + (29498 - 34623.05)^2 + (31980 - 34623.05)^2 + (22764 - 34623.05)^2 + (54190 - 34623.05)^2 + (37756 - 34623.05)^2 + (30129 - 34623.05)^2 + (33980 - 34623.05)^2 + (47909 - 34623.05)^2 + (32200 - 34623.05)^2 + (38120 - 34623.05)^2 = 1527829234.95

Standard deviation = √(1527829234.95/20

s1 = 8740.22

For public Institutions,

n = 20

Mean, x2 = (25469 + 19450 + 18347 + 28560 + 32592 + 21871 + 24120 + 27450 + 29100 + 21870 + 22650 + 29143 + 25379 + 23450 + 23871 + 28745 + 30120 + 21190 + 21540 + 26346)/20 = 25063.15

Summation(x - mean)² = (25469 - 25063.15)^2+ (19450 - 25063.15)^2 + (18347 - 25063.15)^2 + (28560 - 25063.15)^2 + (32592 - 25063.15)^2 + (21871 - 25063.15)^2 + (24120 - 25063.15)^2 + (27450 - 25063.15)^2 + (29100 - 25063.15)^2 + (21870 - 25063.15)^2 + (22650 - 25063.15)^2 + (29143 - 25063.15)^2 + (25379 - 25063.15)^2 + (23450 - 25063.15)^2 + (23871 - 25063.15)^2 + (28745 - 25063.15)^2 + (30120 - 25063.15)^2 + (21190 - 25063.15)^2 + (21540 - 25063.15)^2 + (26346 - 25063.15)^2 = 1527829234.95

Standard deviation = √(283738188.55/20

s2 = 3766.55

This is a test of 2 independent groups. Let μ1 be the mean out-of-state tuition for private institutions and μ2 be the mean out-of-state tuition for public institutions.

The random variable is μ1 - μ2 = difference in the mean out-of-state tuition for private institutions and the mean out-of-state tuition for public institutions.

We would set up the hypothesis. The correct option is

-B. H0: μ1 = μ2 ; H1: μ1 > μ2

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

t = (34623.05 - 25063.15)/√(8740.22²/20 + 3766.55²/20)

t = 9559.9/2128.12528473889

t = 4.49

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [8740.22²/20 + 3766.55²/20]²/[(1/20 - 1)(8740.22²/20)² + (1/20 - 1)(3766.55²/20)²] = 20511091253953.727/794331719568.7114

df = 26

We would determine the probability value from the t test calculator. It becomes

p value = 0.000065

Since alpha, 0.01 > than the p value, 0.000065, then we would reject the null hypothesis. Therefore, at 1% significance level, the mean out-of-state tuition for private institutions is statistically significantly higher than public institutions.

4 0
1 year ago
Solve 5/3x + 1/3x = 13 1/3 + 8/3x then identify x.
belka [17]

After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Step-by-step explanation:

We need to solve the fractions and find value of x.

The given fraction is:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x

Solving:

\frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x\\\frac{5}{3}x+\frac{1}{3}x=\frac{40}{3}+\frac{8}{3}x\\ Subtract\,\,\frac{8}{3}x\,\,on\,\,both\,\,sides:\\ \frac{5}{3}x+\frac{1}{3}x-\frac{8}{3}x=\frac{40}{3}+\frac{8}{3}x-\frac{8}{3}x\\Simplifying:\\ \frac{5x+1x-8x}{3}=\frac{40}{3}\\ \frac{-2x}{3}=\frac{40}{3}\\Multiply\,\,both\,\,sides\,\,by\,\,3\\-2x=40\\x=\frac{40}{-2}\\x=-20

So, After solving \frac{5}{3}x+\frac{1}{3}x=13\frac{1}{3}+\frac{8}{3}x we get value of x = -20

Keywords: Solving fractions

Learn more about Solving fractions at:

  • brainly.com/question/2456302
  • brainly.com/question/1648978
  • brainly.com/question/13168205

#learnwithBrainly

3 0
2 years ago
A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T
Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

8 0
2 years ago
A chi-square test for goodness of fit is used to examine the distribution of individuals across three categories, and a chi-squa
aleksandrvk [35]

Answer:

Equal df

Step-by-step explanation:

Given that a chi square test for goodness of fit is used to examine the distribution of individuals across three categories,

Hence degree of freedom = 3-1 =2

Similarly for a chi-square test for independence is used to examine the distribution of individuals in a 2×3 matrix of categories.

Here degree of freedom = (r-1)(c-1) where r = no of rows and c =no of columns

= (2-1)(3-1) = 2

Thus we find both have equal degrees of freedom.

3 0
2 years ago
Other questions:
  • The chart below shows the number of cakes Jenny bakes each month . What is the mean number of cakes Jenny bakes in a month
    6·2 answers
  • A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 park
    13·1 answer
  • give two examples that show how using parentheses can change the order in which operations are performed in an expression?
    11·1 answer
  • Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)] and select the correct answer below. (2 points)
    9·1 answer
  • 7. A total of $12,000 was invested in two types of bonds. One pays 8% simple interest while the other
    11·1 answer
  • If ce = 7x+4, find the value of x
    7·2 answers
  • You have $60 and your sister has $120. You are saving $14 per week and your sister is saving $10 per week. How
    5·1 answer
  • Triangle ABC is congruent to triangle XYZ. In ΔABC, AB = 12 cm and AC = 14 cm. In △XYZ, YZ = 10 cm and XZ = 14 cm. What is the p
    13·1 answer
  • Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of
    15·2 answers
  • Experiment with different types of polygons, such as a triangle, rectangle, parallelogram, pentagon, hexagon, and so on, and rev
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!