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Karo-lina-s [1.5K]
2 years ago
3

Define step five of the Risk Management (RM) process? As a future Sergeant Major, provide an example and explain what your role

is in the step?
Engineering
1 answer:
Ne4ueva [31]2 years ago
4 0

Answer:

Explanation:

Risk Management includes :  

Risk Identification  

Risk Analysis  

Risk Evaluation  

Risk Response  

Risk Review  

Each of the five stages are performed efficiently to comprehend the Risk and find a way to relieve the risk.  

The Fifth step that is hazard checking and chance audits allude to a procedure where the best possible follow up is done, vulnerabilities are observed and surveyed and remedial moves can be made to ensure that hazard later on. Along these lines, the last advance can be named as a controlling advance to avert future vulnerabilities.  

As a future CSM/SGM, the task that I am taking care of might be looked at with unsure occasions like machine disappointment, changes in the earth like innovative up-degree that may leave my venture in a genuine misfortune, so before beginning the undertaking itself it is essential to investigate the potential vulnerabilities. By perceiving and keeping up an exhaustive rundown of errand dangers, surprising difficulties and hindrances can be killed and brilliant open doors can be recognized.  

My job, particularly at the last stage, is to survey the dangers and ensure that it doesn't happen later on and must be kept away from at any expense and it has been distinguished and an arrangement to moderate such dangers should likewise be set up to beat the hazard and maintain a strategic distance from any monetary misfortune. It helps venture groups and accomplices, less restless. The final product is to moderate the impact of undertaking dangers and hold onto the motivating forces that happen.

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A fuel oil is burned with air in a furnace. The combustion produces 813 kW of thermal energy, of which 65% is transferred as hea
DENIUS [597]

Answer:

im not sure

Explanation:

8 0
2 years ago
A sample of normally consolidated clay was subjected to a CU triaxial compression test that was carried out until the specimen f
QveST [7]

Answer:

Check the explanation

Explanation:

Given

1) CU traixial compression test

2) Devatoric stress at failure  = бd = 50 kN/m^2

3) Confining pressure at failure  = бd = 48 kN/m^2

4) Pore pressure at failure  = u = 18 kN/m^2

5) Unconfined compression stress  = q = 20 kN/m^2

6) Undrained cohesion  = q/2 = 20 kN/m^2

To find:

1) Effective and total stress strength failure envelope

Kindly check the attached image below .

7 0
2 years ago
What is the damped natural frequency (in rad/s) of a second order system whose undamped natural frequency is 25 rad/s and has a
TiliK225 [7]

Answer:

damped natural frequency = 23.84 rad/s

Explanation:

given data

damping ratio = 0.3

undamped natural frequency = 25 rad/s

to find out

damped natural frequency of a second order system

solution

we know that if damping ratio is = 0

then it is undamped system

and if damping ratio is > 1

then it is overdamped system

and  and if damping ratio is ≈ 1

then it is critical damped system

so damped natural frequency of a second order system formula is

damped natural frequency = wn × \sqrt{1-r^2}

here wn is undamped natural frequency and r is damping ratio

damped natural frequency = 25 × \sqrt{1-0.3^2}

damped natural frequency = 23.84 rad/s

3 0
2 years ago
An electric field is expressed in rectangular coordinates by E = 6x2ax + 6y ay +4az V/m.Find:a) VMN if point M and N are specifi
Fittoniya [83]

Answer:

a.) -147V

b.) -120V

c.) 51V

Explanation:

a.) Equation for potential difference is the integral of the electrical field from a to b for the voltage V_ba = V(b)-V(a).

b.) The problem becomes easier to solve if you draw out the circuit. Since potential at Q is 0, then Q is at ground. So voltage across V_MQ is the same as potential at V_M.

c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

Honestly, these things take practice to get used to. It's really hard to explain this.

3 0
2 years ago
A fatigue test was conducted in which the mean stress was 46.2 MPa and the stress amplitude was 219 MPa.
sleet_krkn [62]

Answer:

a)σ₁ = 265.2 MPa

b)σ₂ = -172.8 MPa

c)Stress\ ratio =-0.65

d)Range = 438 MPa

Explanation:

Given that

Mean stress ,σm= 46.2 MPa

Stress amplitude ,σa= 219 MPa

Lets take

Maximum stress level = σ₁

Minimum stress level =σ₂

The mean stress given as

\sigma_m=\dfrac{\sigma_1+\sigma_2}{2}

2\sigma_m={\sigma_1+\sigma_2}

2 x 46.2 =  σ₁ +  σ₂

 σ₁ +  σ₂ = 92.4 MPa    --------1

The amplitude stress given as

\sigma_a=\dfrac{\sigma_1-\sigma_2}{2}

2\sigma_a={\sigma_1-\sigma_2}

2 x 219 =  σ₁ -  σ₂

 σ₁ -  σ₂ = 438 MPa    --------2

By adding the above equation

2  σ₁ = 530.4

σ₁ = 265.2 MPa

-σ₂ = 438 -265.2 MPa

σ₂ = -172.8 MPa

Stress ratio

Stress\ ratio =\dfrac{\sigma_{min}}{\sigma_{max}}

Stress\ ratio =\dfrac{-172.8}{265.2}

Stress\ ratio =-0.65

Range = 265.2 MPa - ( -172.8 MPa)

Range = 438 MPa

8 0
2 years ago
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