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Elena-2011 [213]
2 years ago
9

The elements C and Se have the same electronegativity value, 2.55. Which of the following claims about the compound that forms f

rom C and Se is most likely to be true?
A. The carbon-to-selenium bond is unstable.
B. The carbon-to-selenium bond is nonpolar covalent.
C. The compound has the empirical formula CSe.
D. A molecule of the compound will have a partial negative charge on the carbon atom.
Chemistry
1 answer:
Rom4ik [11]2 years ago
8 0

Answer:

B

Explanation:

Having the same electronegativity means that the both elements will form a nonpolar bond. The shared electrons of the bind will be found equidistant from the nucleus of the two atoms because none has an unusual ability to attract the electrons of a bond towards itself.

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What is the net ionic equation for 2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 6NaOH
tatuchka [14]

Answer:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

Explanation:

First of all, let us balance the equation to give;

2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH

Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.

Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

6 0
2 years ago
TRUE or FALSE. The particles of a gas are packed closely together and don't have as much movement as the particles of a solid or
ddd [48]
Gas particles spread out to fill a container evenly, unlike solids and liquids. Gas is a state of matter that has no fixed shape and no fixed volume. Gases have lower density than other states of matter, such as solids and liquids. Hence above statement is FALSE.
3 0
2 years ago
a 280.0 mL sample of neon exerts a pressure of 660.0 toff at 26.0 celsius. at what temperture would it exert a pressure of 940.0
bixtya [17]

Answer:

T₂ = 669.2 K

Explanation:

Given data:

Initial pressure = 660 torr

Initial temperature = 26 °C (26 +273 = 299 K)

Final volume = 280 mL ( 280/1000 = 0.28 L)

Final pressure = 940.0 torr

Final volume = 0.44 L

Final temperature = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂ = P₂V₂ T₁ /P₁V₁

T₂ = 940 torr × 0.44 L  × 299 K / 660 torr × 0.28 L

T₂ = 123666. 4 torr. L. K / 184.8 torr. L

T₂ = 669.2 K

3 0
2 years ago
Calculate the ph of a solution formed by mixing 150.0 ml of 0.10 m hc7h5o2 with 100.0 ml of 0.30 m nac7h5o2. The ka for hc7h5o2
m_a_m_a [10]

Answer:

4.49

Explanation:

pKa = - log 6.5 x 10⁻⁵

pKa  =4.19

Given that :

Volume = 150 mL = 0.150 L

For solutions:

number of moles of acid = volume × concentration

number of moles of  acid = 0.150 L × 0.10 M = 0.0150

number of moles  of salt = 0.100 L × 0.30 M = 0.0300

total volume = 150 + 100

= 250 mL

= 0.250 L

Concentration = number of moles/ Volume

∴

For [salt] = 0.0300/ 0.250

= 0.12 M

For [acid] = 0.0150/ 0.250

=0.06 M

pH = 4.19 + log 0.12/0.06

=4.49

7 0
2 years ago
A student carries out the precipitation reaction shown below, starting with 0.030 moles of calcium nitrate. The final mass of th
valkas [14]

Answer:

a. Ca₃(PO₄)₂.

b. 0.010 moles of Ca₃(PO₄)₂ can we expect to be produced

c. 3.1g of Ca₃(PO₄)₂

d. Percent yield = 93.5%

Explanation:

a. Based on the reaction:

3Ca(NO₃)₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaNO₃(aq)

<em>3 moles of calcium nitrate reacts with 2 moles of sodium phosphate producieng 1 mole of calcium phosphate.</em>

<em />

As you can see, Ca₃(PO₄)₂ is a solid product -(s)-, that means when the reaction occurs the precipitate produced is the solid,

<h3>Ca₃(PO₄)₂</h3><h3 />

b. As 3 moles of calcium nitrate produce 1 mole of calcium phosphate and there are 0.030 moles of calcium nitrate

0.030 moles Ca(NO₃)₂ × (1 mol Ca₃(PO₄)₂ / 3 moles Ca(NO₃)₂) =

<h3>0.010 moles of Ca₃(PO₄)₂ can we expect to be produced</h3><h3 />

c. As molar mass of Ca₃(PO₄)₂ is 310.18g/mol, the mass of 0.010 moles (The expected mass) is;

0.010 moles Ca₃(PO₄)₂ × (310.18g / mol) =

<h3>3.1g of Ca₃(PO₄)₂</h3><h3 />

d. The percent yield is defined as 100 times the ratio between the obtained yield (That is 2.9g of precipitate, Ca₃(PO₄)₂) and the expected yield, 3.1g of Ca₃(PO₄)₂:

\frac{2.9g}{3.1g} *100

<h3>Percent yield = 93.5%</h3>
7 0
2 years ago
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