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RUDIKE [14]
2 years ago
6

Which compound has the lowest vapor pressure at 50°C?

Chemistry
2 answers:
Mnenie [13.5K]2 years ago
7 0

Answer : Option A) Ethanoic Acid


Explanation : Ethanoic acid has the lowest vapor pressure i.e 0.08 atm at the temperature of 50°C compared to the other given options.


The vapour pressure of propanone at 50°C is 0.84 atm

Ethanol has vapour pressure as 0.30 atm at 50°C

water has vapour pressure of 0.12 atm at 50°C.


prisoha [69]2 years ago
6 0

Answer : The correct option is, (1) ethanoic acid.

Explanation :

The relation between the boiling point and the inter-molecular force of attraction is that the higher the boiling point, the stronger the inter-molecular force of attraction that means it requires more energy to breaks the forces between the molecules. Or, the higher the boiling point lower will be the vapor pressure.

In ethanoic acid, the hydrogen bonding will be stronger as compared to the propanone, ethanol and water.

In propanone, the dipole-dipole interaction occurs.

In ethanol and water, the hydrogen bonding occurs but polarity will be less.

Hence, ethanoic acid has the lowest vapor pressure at 50^oC

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34.62 mL of 0.1510 M NaOH was needed to neutralize 50.0 mL of an H2SO4 solution. What is the concentration of the original sulfu
Igoryamba

0.1045M is the concentration of the original sulfuric acid solution

Explanation:

Titration is done to know the volume or concentration of unknown electrolyte.

Data given:

volume of acid = 50 ml

molarity of acid =?

volume of base NaOH = 34.62 ml

molarity of the base = 0.1510

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Macid x Vacid = Mbase  x V base

Putting the values in above equation:

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If 25.0 g of NH₃ and 45.0g of O₂ react in the following reaction, what is the mass in grams of NO that will be formed? 4 NH₃ (g)
Allisa [31]

Answer:

The correct answer would be : 33.8 g

Explanation:

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= 1*14.01 + 3*1.008  = 17.034 g/mol

mass(NH3)= 25.0 g  (given)

number of mol of NH3,

n = mass of NH3/molar mass of NH3

=(25.0 g)/(17.034 g/mol)

= 1.468 mol

Now,

Molar mass of O2

= 32 g/mol

mass(O2)= 45.0 g

similar as ammonia

n (O2)=(45.0 g)/(32 g/mol)

= 1.406 mol

Balanced chemical equation is:

4 NH3 + 5 O2 ---> 4 NO + 6 H2O

1.83456 mol of O2 is required  for 1.46765 mol of NH3

by the calculation we have only 1.40625 mol of O2

Thus, the limiting agent will be - O2

now the Molar mass of NO,

= 1*14.01 + 1*16.0

= 30.01 g/mol  (similar formula used for NH3)

Balanced equation :

mol of NO formed = (4/5)* moles of O2

= (4/5)×1.40625  (from above calculation)

= 1.125 mol

mass of NO = number of moles × molar mass

= 1.125*30.01

= 33.8 g

Thus, the correct answer would be : 33.8 g

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