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victus00 [196]
2 years ago
9

If STUDENT and COURSE participate in a relationship, this is an example of a(n):

Business
1 answer:
Svet_ta [14]2 years ago
6 0

If student and course participate, that relationship is called a Binary Relationship

Explanation:

Binary Entity:

it can be defined as the relationship between 2 different entities.

The binary entity is of 3 types namely

  • one to one (eg: person and diving license)
  • one to many ( eg: project and employee )
  • many to many (eg: student and books)

The binary  of teacher and subject can be explained by

<em>teacher</em> → teaches → <em>subject</em>

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Which of the following is TRUE regarding​ computer-aided design?
Inessa [10]

Answer:

The answer is Letter B

Explanation:

It is the use of computers to interactively design products and prepare engineering documentation.

8 0
2 years ago
When using ________ financing, the company incurs a legal obligation to repay the amount borrowed. debt equity retained earnings
Leni [432]
When using Debt financing, the company incurs a legal obligation to repay the amount borrowed. Retained earnings assign to the percentage of net acquiring not to paid out as dividends, but retained by the company to be reinvested in its core business, or to pay a debt.
6 0
2 years ago
The allotment of narrow, specialized portions of a large tasks to specific workers is known as the:
Oksi-84 [34.3K]

The answer is division of labor. It is the segregation of tasks in any system so that applicants may specialize. Individuals, nations, and organizations are gifted with or obtain particular competencies and either form mixtures or skill to take advantage of the capabilities of others in adding to their own. 

8 0
2 years ago
Suppose the daily change in price of a stock is normally distributed with mean = .20 and standard deviation = .30. What price ch
uranmaximum [27]

Answer:

a=0.2 -0.674*0.3=-0.00235

So the value that separates the bottom 25% of data from the top 75% is -0.00235.  

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(0.2,0.3)  

Where \mu=0.2 and \sigma=0.3

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.75   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=0.2 -0.674*0.3=-0.00235

So the value that separates the bottom 25% of data from the top 75% is -0.00235.  

4 0
2 years ago
Western Industrial Products is considering a project with a five-year life and an initial cost of $220,000. The discount rate fo
Tems11 [23]

Answer:

875 units or less

Explanation:

5 year project $220,000

discount rate 11%

cash flow per year = 2,900 units x $40 = $116,000

after year 3, the project's assets should have a salvage value of $60,000

year                    cash flow

0                         -220,000

1                             116,000

2                            116,000

3                            116,000

4                            116,000

5                            116,000

the project's NPV = $208,724

year                    cash flow

0                         -220,000

1                             116,000

2                            116,000

3                            176,000

the NPV of the first 3 years, including salvage value = $107,342

the difference between both NPVs = $208,724 - $107,342 = $101,382

to determine the number of units sold to make abandoning the project more profitable:

101,382 = x/1.11⁴ + x/1.11⁵ = 0.65873x + 0.59345x = 1.25218x

x = 101,382 / 1.25218 = 80,964 / $40 per unit = 2,024.1 ⇒  2,025 units

so the units sold during years 4 and 5 should be = 2,900 - 2,025 = 875

if total sales lower to 875 units during years 4 and 5, the cash flows should be:

year                    cash flow

0                         -220,000

1                             116,000

2                            116,000

3                            116,000

4                            35,000

5                            35,000

the NPV = $107,297, which is actually lower than the NPV obtained by abandoning the project in year 3.

6 0
2 years ago
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