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igomit [66]
1 year ago
7

A circle with radius of \greenD{6\,\text{cm}}6cmstart color #1fab54, 6, start text, c, m, end text, end color #1fab54 sits insid

e a circle with radius of \blueD{9\,\text{cm}}9cmstart color #11accd, 9, start text, c, m, end text, end color #11accd.
What is the area of the shaded region?

Round your final answer to the nearest hundredth

Mathematics
1 answer:
Diano4ka-milaya [45]1 year ago
3 0

Answer: 141 cm^{2}

Step-by-step explanation:

We have two circles:

Cirlce 1, with a radius r=6 cm and area A_{1}:

A_{1}=\pi r^{2}

And Cicle 2, with a radius R=9 cm and area A_{2}:

A_{1}=\pi R^{2}

Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:

A=A_{2}-A_{1}=\pi R^{2}-\pi r^{2}

A=\pi (R^{2}- r^{2})

A=\pi ((9cm)^{2}- (6cm)^{2})

Finally:

A=141.37 cm^{2} \approx 141 cm^{2}

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The edges of three squares are joined together to form a right triangle with legs of lengths R & S and a hypotenuse of lengt
dezoksy [38]

Answer:

R^{2} + S^{2}  = T^{2}

Step-by-step explanation:

the pythagorean theorem

8 0
1 year ago
Simplify the square root of four over the cubed root of four. four raised to the five sixths power four raised to the one sixth
romanna [79]

Answer:

(B)4^{1/6}

Four raised to the one-sixth power

Step-by-step explanation:

We want to simplify:  \dfrac{\sqrt{4} }{\sqrt[3]{4} }

First, we apply the fractional law of indices to each term.

\text{If  } a^{1/x}=\sqrt[x]{a},$ then:\\\sqrt{4}=4^{1/2}\\\sqrt[3]{4}=4^{1/3}

We then have:

\dfrac{\sqrt{4} }{\sqrt[3]{4} }=\dfrac{4^{1/2} }{4^{1/3} }\\$Applying the division law of indices: \dfrac{a^m }{a^n }=a^{m-n}\\\dfrac{4^{1/2} }{4^{1/3} }=4^{1/2-1/3}\\\\=4^{1/6}

The correct option is B.

7 0
1 year ago
Triangle A B C is reflected across line m to form triangle A prime B prime C prime. Triangle A prime B prime C prime is rotated
Helga [31]

Answer:

  1. reflection across line m
  2. rotation about point A'

Step-by-step explanation:

The problem statement tells you exactly what the transformations are.

The first transformation is reflection across line m.

The second transformation is rotation about point A'.

_____

These are both rigid transformations, so ΔABC ≅ A'B''C''.

6 0
1 year ago
Simplify the expression 3x(x – 12x) + 3x2 – 2(x – 2)2. Which statements are true about the process and simplified product? Check
olasank [31]
We have the expression:
3x(x-12x) + 3x^2 - 2(x-2)^2

First, we will expand the power 2 bracket as follows:
3x(x-12x) + 3x^2 - 2(x^2 - 4x +4)

Then, we will get rid of the brackets as follows:
3x^2 - 36x^2 + 3x^2 - 2x^2 + 8x - 8

Now, we will gather the like terms and add them as follows:
-32 x^2 + 8x - 8

We can take the 8 as a common factor:
8 ( -4x^2 + x -1)
3 0
1 year ago
Let p denote the proportion of students at a particular university that use the fitness center on campus on a regular basis. For
9966 [12]

Answer:

a) P-value = 0.0968

b) P-value = 0.2207

c) P-value = 0.0239

d) P-value = 0.0040

e) P-value = 0.5636

Step-by-step explanation:

As the hypothesis are defined with a ">" sign, instead of an "≠", the test is right-tailed.

For this type of test, the P-value is defined as:

P-value=P(z>z^*)

being z* the value for each test statistic.

The probability P is calculated from the standard normal distribution.

Then, we can calculate for each case:

(a) 1.30

P-value=P(z>1.30) = 0.0968

(b) 0.77

P-value=P(z>0.77) = 0.2207

(c) 1.98

P-value=P(z>1.98) = 0.0239

(d) 2.65

P-value=P(z>2.65) = 0.0040

(e) −0.16

P-value=P(z>-0.16) = 0.5636

7 0
1 year ago
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