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igomit [66]
2 years ago
7

A circle with radius of \greenD{6\,\text{cm}}6cmstart color #1fab54, 6, start text, c, m, end text, end color #1fab54 sits insid

e a circle with radius of \blueD{9\,\text{cm}}9cmstart color #11accd, 9, start text, c, m, end text, end color #11accd.
What is the area of the shaded region?

Round your final answer to the nearest hundredth

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
3 0

Answer: 141 cm^{2}

Step-by-step explanation:

We have two circles:

Cirlce 1, with a radius r=6 cm and area A_{1}:

A_{1}=\pi r^{2}

And Cicle 2, with a radius R=9 cm and area A_{2}:

A_{1}=\pi R^{2}

Since Circle 1 is inside Circle 2 and assuming the area of the shaded region is the shown in the attached image, its area is:

A=A_{2}-A_{1}=\pi R^{2}-\pi r^{2}

A=\pi (R^{2}- r^{2})

A=\pi ((9cm)^{2}- (6cm)^{2})

Finally:

A=141.37 cm^{2} \approx 141 cm^{2}

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It would take 200 minutes for 200 nurses to measure the blood pressure of 200 patients.
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2 years ago
I have a map where indy and ft. Wayne are 3 centimeters apart. Kokomo and indy are 1.5 cm apart on the map. If i know that indy
marta [7]

Indy and kokomo will be 60 miles apart in real life.

<u><em>Explanation</em></u>

On the map, Indy and ft. Wayne are 3 cm apart and Kokomo and Indy are 1.5 cm apart.

So, <u>the ratio </u>of the distance between Indy and ft. Wayne to the distance between Kokomo and Indy will be:  3: 1.5 = 30:15= 2:1

Now, lets assume that real distance between Indy and ft. Wayne is  2x cm and real distance between Kokomo and Indy is  x  cm.

Given that, the real distance between Indy and ft. Wayne is 120 miles.

That means....

2x= 120\\ \\ x= \frac{120}{2}=60

So, Indy and kokomo will be 60 miles apart in real life.

3 0
2 years ago
Jose drove from newyork to Florida. Resting for 1 hour for every 5 hours he drove. if he drove for 35 hours. how many hours did
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7 0
1 year ago
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Joyce uses 3/10 bag of chocolate chips for each batch of cookies she makes. What is the least number of batches Joyce can make i
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2 years ago
The track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. Then they are able
konstantin123 [22]

Answer: 15.7 minutes

Step-by-step explanation:

Let x be the time in the beginning (in minutes).

Given: The track team is trying to reduce their time for a relay race.

First they reduce their time by t_1=2.1 minutes.

Then they are able to reduce that time by t_2=10

If their final time is 3.96 minutes, then

x-t_1-t_2=3.6\\\Rightarrow\ x=3.6+t_1+t_2\\\Rightarrow\ x=3.6+2.1+10\\\Rightarrow\ x= 15.7

Hence, their beginning time was 15.7 minutes.

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2 years ago
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