Question

Emily has 12 fruits in her bowl. She has 3 apples, 5 bananas, 1 pear and 3 oranges. A fruit is selected at random. What is the probability that the fruit is an orange or a pear? A. 56 B. 23 C. 12 D. 13

Answer 1

Answer: The probability that the fruit is an orange or a pear is $\dfrac{1}{3}$ .

Step-by-step explanation:

Given : Emily has 12 fruits in her bowl.

She has 3 apples, 5 bananas, 1 pear and 3 oranges.

A fruit is selected at random.

P(orange)  = $\dfrac{\text{Number of oranges}}{\text{Total fruits}}$

$=\dfrac{3}{12}$

P(pear)= $\dfrac{\text{Number of pears}}{\text{Total fruits}}$

$=\dfrac{1}{12}$

Since both events of selecting orange and pear are mutually exclusive , so

The probability that the fruit is an orange or a pear = P(orange) + P(pear)

$=\dfrac{3}{12}+\dfrac{1}{12}=\dfrac{4}{12}=\dfrac{1}{3}$

Therefore , the probability that the fruit is an orange or a pear is $\dfrac{1}{3}$ .