Question

How many ounces of iodine worth 80 cents an ounce must be mixed with 50 ounces of iodine worth 48 cents an ounce so that the mixture can be sold for 60 cents an ounce?

Answer 1

Answer:

I think it is 30

Step-by-step explanation:

Answer 2

Answer:

30 ounces of iodine worth 80 cents an ounce

Step-by-step explanation:

Let

x ----> ounces of iodine worth 80 cents an ounce

we know that

The ounces of iodine (x) worth 80 cents an ounce mixed with 50 ounces of iodine worth 48 cents an ounce must be equal to the mixture (x+50) worth 60 cents an ounce

The linear equation that represent this situation is

$0.80x+0.48(50)=(x+50)(0.60)$

solve for x

$0.80x+24=0.60x+30\\0.80x-0,60x=30-24\\0.20x=6\\x=30\ ounces$