Sunlight is the main change! sun light cannot penetrate into the deep layers of the ocean and availability of oxygen is also low there. this causes the considerable amount of organisms to live in the upper layers of the ocean and we can only observe decomposing organisms in the deeper layers!
<span>Connective tissue supports the framework of the liver, and epithelial tissue protects the liver.
Connective tissue holds the liver in place during movement, and epithelial tissue forms the lining of the liver.
Connective tissues are mainly used in forming support networks within tissues and Epithelial tissue tend to line the organs and form protective cell layers.</span>
A few enzymes<span> exhibit absolute </span>specificity<span>; that is, they will catalyze only one particular reaction. Other </span>enzymes<span> will be specific for a particular type of chemical bond or functional group. In general, there are four distinct types of </span>specificity<span>: Absolute </span>specificity<span> - the </span>enzyme<span> will catalyze only one reaction.</span>
Under extreme temperatures Enzymes become inactivated or denatured. due to this reason there will be no change in Photosynthesis despite a change in Light intensity.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%