Question

A bag contains 20 balls: 8 red balls and 12 blue balls. Six of these balls are classified as "heavy", and three of the heavy balls are red. If a ball is chosen at random from the bag, what is the probability that it is red or heavy

Answer 1

Answer:

P(red or heavy)= 11/20

Step-by-step explanation:

A bag contains 20 balls: 8 red balls and 12 blue balls

six balls are heavy- 3 heavy red balls and 3 heavy blue balls

In 8 red balls, 3 are heavy and 5 are light

In 12 blue balls, 3 are heavy and 9 are light

Probability (red or heavy)=P(red) +P(heavy) -P(red and heavy)

$P(read \ or \ heavy)= \frac{8}{20} +\frac{6}{20} -\frac{3}{20} =\frac{11}{20}$