In five weeks, there are 35 days. So, the average drop in temperature per day is 40/35 = 8/7 degrees per week. Then in 1 week, 8/7 degrees per day * 7 days per week = 8 degrees per week.Therefore there are 8 degrees drop of temperature in 1 week.
Answer:
The probability is 0.31
Step-by-step explanation:
To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.
In this case, the event of interest is choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is
, where
. We have that 
Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in 
So the probability of having 3 laser printers and 3 inkjets is given by

A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm
Answer:
FG || BC.
Step-by-step explanation:
In the diagram, which is not drawn to scale, DE | FG || BC.
For this case what you should do is create the equation based on:
"She knows that the volume of the container is equal to one-third of the product, the square of the radius of the base of the container, and the height of the container"
We have then that the Volume is given by:
V = (1/3) * (r ^ 2) * (h)
where,
r: radius of the base.
h: height of the container.
answer
The volume of the container is calculated with the following equation:
V = (1/3) * (r ^ 2) * (h)