answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slega [8]
1 year ago
7

A stadium has 10500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sec

tions. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.
Mathematics
1 answer:
Hunter-Best [27]1 year ago
4 0

Answer:

1). 875 seats

2). 25 rows in each section

3). $8400

4). Saving of $360

5). 2105 tickets remained unsold

6). x = 16

Step-by-step explanation:

This question is incomplete; here is the complete question.

A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal  sections: 2 premium sections and 10 standard sections. A seat at the premium section  costs $48 per game. A seat at the standard section costs $27 per game.

1. How many seats are there in each section?

2. If there are 35 seats in each row, how many rows are in each section?

3. If all the seats in the premium section are sold out for a game, how much will the  stadium get from those ticket sales?

4. There are 50 games in each season. A season pass costs $2,040. A season pass  holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?

5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were  left?

6. Write an equation using “x” and then solve  the equation. Each VIP boxes can seat X  people. If all the seats and VIP boxes are  filled up, there are 10,628 audience in the stadium.

1). Number of seats in the stadium = 10500

Number of sections = 2 premium + 10 standard = 12

Number of seats in each section = \frac{10500}{12}=875

2). If the number of seats in each row = 35

Then number of rows in each section = \frac{875}{35}=25

3). Number of seats in 2 premium sections = 2×875 = 1750

Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000

4). Cost of one ticket in premium section = $48 per game

If the games planned in one season = 50

Then cost of the tickets = 48×50 = $2400

Cost of the season ticket = $2040

Saving on the purchase of one season ticket = 2400 - 2040 = $360

5). For a night game number of tickets sold = 8395

Total number of seats in the stadium = 10500

Tickets remained unsold = 10500 - 8395 = 2105

6). Number of seats in each VIP box = x

Number of VIP boxes = 8

Number of seats in 8 VIP boxes = 8x

Total number of tickets sold = 10500 + 8x

Total number of audience in the stadium = 10628

Then the equation will be

8x + 10500 = 10628

8x = 10628 - 10500

x = \frac{128}{8}=16

You might be interested in
Calculate the side lengths a and b to two decimal places
Talja [164]

Answer:

The answer is (D) ⇒ a = 11.71 , b = 15.56

Step-by-step explanation:

* In ΔABC

∵ m∠A = 45°

∵ m∠B = 110°

∴ m∠C = 180 - 45 - 110 = 25°

By using the sin Rule

∵ a/sin(A) = b/sin(B) = c/sin(C)

∵ c = 7

∴ a/sin(45) = b/sin(110) = 7/sin(25)

∴ a = (7 × sin(45)) ÷ sin(25) = 11.71

∴ b = (7 × sin(110)) ÷ sin(25) = 15.56

∴ The answer is (D)

5 0
1 year ago
There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

A = a + (A \cap B)

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and A \cap B is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

B = b + (A \cap B)

188 who have taken courses in both calculus and discrete mathematics.

This means that A \cap B = 188

212 who have taken a course in discrete mathematics

This means that B = 212

345 students at a college who have taken a course in calculus

This means that A = 345

How many students have taken a course in either calculus or discrete mathematics

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

369 students have taken a course in either calculus or discrete mathematics

4 0
1 year ago
Alinethatincludesthepoint(2, 7)has slope of 5 . what isitsequationin slope -intercept form
Vesna [10]
10? Im not sure though my friend just told me it was 10
8 0
1 year ago
In estimating the mean score on a fitness exam, we use an original sample of size n = 30 and a bootstrap distribution containing
ioda

Answer:

C. 67.5 to 72.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The width of the interval is determined by it's margin of error, which is given by the following formula:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

So, as n increases, the margin of error decreases, and the interval gets smaller.

Using 10,000 bootstrap samples for the distribution:

We increase the sample size, which means that the interval gets smaller.

We had 67 to 73, since it got smaller, it will be from a value higher than 67 to a value lower than 73.

So the correct answer is:

C. 67.5 to 72.

8 0
2 years ago
According to the scatterplot below, which statement is correct? A graph titled Courses Completed versus Remaining Credits Needed
kondaur [170]

Answer:

Option B.

Step-by-step explanation:

It is given that a graph titled Courses Completed versus Remaining Credits Needed to Graduate has courses completed on the x-axis and Credits need to graduate on the y-axis.

Points plotted are (4, 110), (8, 76), (16, 63), (20, 53), (24, 33).

Since, x-axis represents the courses completed, therefore the input, or independent variable is courses completed.

Since, y-axis represents the Credits need to graduate, therefore the output, or dependent variable is Credits need to graduate.

Therefore, the correct option is B.

6 0
1 year ago
Read 2 more answers
Other questions:
  • Evan is walking 2 1/8 miles to his aunt's house. He has already walked 6/8 mile. How much further does Evan have to go? Solve th
    13·1 answer
  • Two brothers build a pyramid-shaped fort. If the fort is 8 feet wide at its base, what expression could be used to calculate the
    15·2 answers
  • Laurie has $46,000 invested in stocks. The amount invested in stocks is $8,000 less than three times the amount invested in bond
    13·1 answer
  • A dime has the same value of 10 pennies. Marley brought 290 pennies to the bank. How many dimes did Marley get?
    10·1 answer
  • Karlie makes $8.00 per hour. Karlie worked 16 hours in one week. Karlie wants to purchase a bike that costs $70.00. How much mon
    12·2 answers
  • The distribution of the number of siblings for students at a large high school is skewed to the right with mean 1.8 siblings and
    12·1 answer
  • 2. Juanita is asked to write the standard equation of a
    7·1 answer
  • ther a Point Is Part of the Solution Decide whether each point is a solution to the system. y<=3x+4 and y<=3x-2 (0, –2) (5
    12·1 answer
  • The bus routes in a city run on average every 15 minutes. The route times can vary by three minutes. Which absolute value equati
    8·1 answer
  • the cost of a 12-ounce bag of cashews is $5.86 what is the cost per ounce of the cashews to the nearest penny
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!