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Vinil7 [7]
2 years ago
5

It is recommended that you work this out on graph paper to help answer the questions. Nina plots the locations of 4 places on a

coordinate grid as given below (It is recommended that you work this out on graph paper to help answer the questions.):
Her house is at (−4, 10).
Her school is at (−4, 3).
The community center is at (2, 3).
The grocery store is at (−4, −6).

Part A: Use absolute values to calculate the distance in units from Nina's house to her school. Show your work. (4 points)

Part B: Is the total distance from Nina's house to the school to the grocery store greater than the total distance from Nina's house to the school to the community center? Justify your answer. (6 points)​
Mathematics
1 answer:
AlexFokin [52]2 years ago
7 0
A. 7 units
10-3=7
B. To the grocery store is greater
Home to school north 7 to grocery store 16 south 23 units
Home to school north 7 to community center 6 units east 12 units
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Answer:

The answer is correct

Step-by-step explanation:

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2 years ago
The XO Group Inc. conducted a survey of 13,000 brides and grooms married in the United States and found that the average cost of
slavikrds [6]

Answer:

a) 0.0392

b) 0.4688

c) At least $39,070 to be among the 5% most expensive.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29858, \sigma = 5600

a. What is the probability that a wedding costs less than $20,000 (to 4 decimals)?

This is the pvalue of Z when X = 20000. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.0392.

b. What is the probability that a wedding costs between $20,000 and $30,000 (to 4 decimals)?

This is the pvalue of Z when X = 30000 subtracted by the pvalue of Z when X = 20000.

X = 30000

Z = \frac{X - \mu}{\sigma}

Z = \frac{30000 - 29858}{5600}

Z = 0.02

Z = 0.02 has a pvalue of 0.5080.

X = 20000

Z = \frac{X - \mu}{\sigma}

Z = \frac{20000 - 29858}{5600}

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

So this probability is 0.5080 - 0.0392 = 0.4688

c. For a wedding to be among the 5% most expensive, how much would it have to cost (to the nearest whole number)?

This is the value of X when Z has a pvalue of 0.95. So this is X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 29858}{5600}

X - 29858 = 5600*1.645

X = 39070

The wedding would have to cost at least $39,070 to be among the 5% most expensive.

5 0
2 years ago
Calle had five times as many stickers as sara did and twice as many as juniper. Juniper had 25 stickers. How many stickers did t
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Calle: has twice as many as Juniper so = 2*25 = 50

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3 0
2 years ago
Jason ran 5/7 of the distance around the school track. Sara ran 4/5 of Jason's distance. What fraction of the total distance aro
masha68 [24]
Jason: 5/7
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7 0
2 years ago
In a college archaeology class, 78 students are going to a dig site to find and study artifacts. The dig site has been divided i
const2013 [10]

Answer: There are 9 sections of group of 2 and 15 sections of group of 4.

Step-by-step explanation:

Since we have given that

Let the number of sections of group of 2 students be 'x'.

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So,total number of sections = 24

According to question, it becomes,

x+y=24----------------(1)

Number of students going to dig = 78

So, it becomes,

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From, eq(1), we get that

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So, the value of x is 24-15=9

Hence, there are 9 sections of group of 2 and 15 sections of group of 4.

4 0
2 years ago
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