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Elodia [21]
2 years ago
11

10-kg batch of a food product has a moisture content of175% dry basis. Calculate the amount of water to beremoved from the produ

ct to reduce the moisture content to15% wet basi
Mathematics
1 answer:
sleet_krkn [62]2 years ago
3 0

Answer:

4.9kg of water

Step-by-step explanation:

Dry basis is the percentage ratio of moisture amount to amount of dry product which is 175%

Ratio of moisture amount to dry product = 175 : 100

Mass of food product = 10kg

Amount of moisture in food product = 175/175+100 × 10kg = 175/275 × 10kg = 6.4kg

Wet basis is the percentage ratio of the moisture amount to the total weight of material which is 15%

Ratio of moisture amount to total weight of material is 15 : 100

Amount of moisture in food product = 15/100 × 10kg = 1.5kg

Amount of water contained in the final product = 1.5kg

Amount of other components in the food product = 10kg - 6.4kg = 3.6kg

Total amount = 1.5kg + 3.6kg = 5.1kg

% of water = 1.5kg/5.1kg × 100 = 29%

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The area of Miguel’s rectangular garden is 450 square feet. The garden is 9 feet wide.
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Answer: 118 feet

Step-by-step explanation:

For a rectangular shape: Area = W × L

450 = 9 × L

450 ÷ 9

L = 50

Perimeter of a rectangular shape = 2L + 2W

Perimeter = (2 × 50) + (2 × 9)

= 100 + 18 = 118 feet

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2 years ago
A psychologist is collecting data on the time it takes to learn a certain task. For 50 randomly selected adult subjects, the sam
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Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

s=4.00

Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

t_{n-1,\alpha/2}=t_{49, 0.025}= 2.009575\approx2.010

Confidence interval : \overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}

16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

Required 95% confidence interval :  (15.263,\ 17.537)

8 0
2 years ago
A tunnel is in the shape of a parabola. The maximum height is 16 m and it is 16 m wide at the base, as shown below.
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Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4

y=ax^2→y=-(1/4)x^2

7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
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Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m

Please, see the attached file.

Answer: Third option 15.75 m

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Answer:

Option D

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correct answer on edge :)

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Leon needs to save more than $350 to buy a new bike. He has $130 saved so far, and he plans to save $20 each week until he has e
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