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avanturin [10]
2 years ago
9

A basketball is rolling with a velocity of 0.5 meters/second relative to the ground and due north. A tennis ball is rolling with

a velocity of 0.25 meters/second relative to ground in the same direction of the basketball. Find the velocity of the basketball relative to tennis ball.
Mathematics
1 answer:
RSB [31]2 years ago
5 0
Ok so let me help you like this: We need to understand first that <span>The basketball has a higher speed, that means that the tennis ball will never catch up. so what we need to use is the formula
</span>Vr=Vb--Vt 
<span>=0.5-0.25=0.25
</span>So the speed is <span>0.25m/s
Hope this is useful</span>
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Step-by-step explanation:

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Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 6, p = 0.2

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if P(X \geq 5) < 0.05

We have that

P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05

Since P(X \geq 5) < 0.05, 5 is a significantly high number of adults who believe in reincarnation in this sample.

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2 years ago
Kelly's basketball team made a total of 33 two points and three point baskets in their game last week. If her team scored a tota
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Answer:

They make <u>27</u> two points basket.

Step-by-step explanation:

Given:

Kelly's basketball team made a total of 33 two points and three point baskets in their game last week.

If her team scored a total of 72 points.

Now, to find the number of two points baskets they make.

Let the two points basket be x.

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So, total number of two points and three point baskets are:

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y=33-x\ \ \ .........(1)

Now, the total points team scored:

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Substituting the value of y from equation (1) we get:

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<em>Subtracting both sides by 99 we get:</em>

2x-3x=-27

-x=-27

<em>Dividing both sides by -1 we get:</em>

x=27.

The the two points basket = 27.

Therefore, they make 27 two points basket.

4 0
2 years ago
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