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Artyom0805 [142]
2 years ago
9

Glenda makes an online purchase of 4 picture frames for $12.95 each and 4 mats for $5.89 each. The site says that taxes paid by

the customer are 6.5% of the total purchase price. Shipping charges are based on the following table:
Mathematics
2 answers:
Deffense [45]2 years ago
7 0
3.40 i the correct answer for this
Agata [3.3K]2 years ago
5 0
<span>Glenda has been over charged by $3.40 for her purchase. Below is the solution: First you have to multiply the prices for frames and mats by number of pieces: 5.89 x 4 = 23.56 12.95 x 4 = 51.80 Then add amount: 23.56 + 51.80 = 75.36 Then multiply by 6.5% $75.36 * 6.5% = $4.90 $75.36 + $4.90 = $80.26 $80.26 + $8.20 = $88.46 $91.86- $88.46 = $3.40 </span>
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A water trough has two congruent isosceles trapezoids as ends and two congruent rectangles as sides.
BlackZzzverrR [31]

Answer:

Part a) The exterior surface area is equal to 160\ ft^{2}

Part b) The volume is equal to 240\ ft^{3}

Part c) The volume water left in the trough will be 84\ ft^{3}

Step-by-step explanation:

Part a) we know that

The exterior surface area is equal to the area of both trapezoids plus the area of both rectangles

so

<em>Find the area of two rectangles</em>

A=2[12*5]=120\ ft^{2}

<em>Find the area of two trapezoids</em>

A=2[\frac{1}{2}(8+2)h]

Applying Pythagoras theorem calculate the height h

h^{2}=5^{2}-3^{2}

h^{2}=16

h=4\ ft

substitute the value of h to find the area

A=2[\frac{1}{2}(8+2)(4)]=40\ ft^{2}

The exterior surface area is equal to

120\ ft^{2}+40\ ft^{2}=160\ ft^{2}

Part b) Find the volume

We know that

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=20\ ft^{2}

L=12\ ft

substitute

V=20(12)=240\ ft^{3}

Part c)

<em>step 1</em>

Calculate the area of the trapezoid for h=2 ft (the half)

the length of the midsegment of the trapezoid is (8+2)/2=5 ft

A=\frac{1}{2}(5+2)(2)=7\ ft^{2}

<em>step 2</em>

Find the volume

The volume is equal to

V=BL

where

B is the area of the trapezoidal face

L is the length of the trough

we have

B=7\ ft^{2}

L=12\ ft

substitute

V=7(12)=84\ ft^{3}

4 0
2 years ago
Store A charges $1,200 for repairs with a 6 percent sales tax. Store B charges $1,350 with a 7 percent sales tax. Explain how yo
Lilit [14]

Answer:

The total repair cost for each store is the cost of repairs added to the sales tax. The amount of money saved will be the difference between the two total costs.

6 0
2 years ago
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A lightbulb manufacturer ships large consignments of lightbulbs to big industrial users. When the production process is function
Mashutka [201]

Answer:

a) P[ Pf | Ptd ]  = 0,428

b) P[ Pf | Nd ]  = 0,692

Step-by-step explanation:

We will call:

Pf  Probability of functioning correctly    60 %   or 0.6

Pfn  Probability of malfunctioning   40 %  or  0,4

PNd Probability of nondefective bulb

D₁  Probability of defective bulb when the process is correctly working

D₂  Probability of defective bulb when the process is in malfunction condition

Ptd Total probability of defective bulbs

Then applying theorem´s Bayes  have

P [ A | B ]  =  P(A) * P [ B | A ] / P(B)

a) Probabilty of the process is functioning correctly given that we pick up a defective bulb

The total probability of defective bulbs is equal to, probabilty of defective bulbs when the process is Ok, plus probability of defective bulbs when the process  is in malfunctioning condition, therefore

Ptd  = (0,6)*(0,25) + (0,40)*(0,50) = 0,15 * 0,20 = 0,35

P[ Pf | Ptd ]  =  Pf * P [ Pd | Pf ] / Ptd    =  0,6 * 0,25 / 0,35

P[ Pf | Ptd ]  = 0,428

b)  P [ Pf | Nd ]

P[ Pf | Nd ]  =  Pf *  P [Nd | Pf ] / PNd

PNd  = 1 - Ptd    =  1 - 0,35   =  0,65

P[ Pf | Nd ]  = 0,6 * 0,75 / 0,65   =  0,692

P[ Pf | Nd ]  = 0,692

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2 years ago
A rectangle that has an area of 357 square inches is 17 inches wide. Using the formula for area (4072-01-01-03-00_files/i0260000
Masja [62]
A = L * W
A = 357
W = 17

357 = 17L
357 / 17 = L
21 = L <== length is 21 inches

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Both copy machines reduce the dimensions of images that are run through the machines. Which
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<u>Answer:</u>

<u>As the number of copies increases The dimension of images continues to decrease until reaching 0. </u>

<u>Step-by-step explanation:</u>

Remember, that the term dimension refers not to an unlimited/unending length but to a specific measurable length.

Therefore, as both copy machines reduces the dimensions of images that are run through the machines over time the dimensions of images would decrease until reaching 0; Implying that the dimension is so small to be invisible, in a sense becoming 0.

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