Answer:
Ps=19.62N
Explanation:
The detailed explanation of answer is given in attached files.
A floor in an office building is made of a reinforced concrete slab 10 in. deep and spans 20 ft. For the purposes of calculating
the tributary load you can assume the slab is 10 ft. wide. This scenario can be modelled as a simply supported beam, 20 ft. long, 10 in. deep and 10 ft. wide.
Calculate the maximum factored maximum moments and shears on this structure using the appropriate load combinations discussed in class.
Note which loading combination is critical.
You can assume the uniform live load is 50 psf.
Hint: since this is not a member that carries lateral load, there are no significant wind or earthquake loads contributing to the shear and moments in the member.
Since this is not on the roof there are no roof or snow loads. h = 10 in. 20 ft.
Calculate the maximum factored maximum moments and shears on this structure using the appropriate load combinations discussed in class.
Note which loading combination is critical.
You can assume the uniform live load is 50 psf.
Hint: since this is not a member that carries lateral load, there are no significant wind or earthquake loads contributing to the shear and moments in the member.
Since this is not on the roof there are no roof or snow loads. h = 10 in. 20 ft.
1 answer:
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The total amount of daily heat transfer is 1382.38 M w.
The temperature on the outside surface of the gypsum plaster insulation is 17.96 ° C.
<u>Explanation:</u>
Given data,
= 10° C
= 250 w/
k
Pipe length = 20 m
Inner diameter = 6 cm,
= 3 cm
Outer diameter = 8 cm,
= 4 cm
The thickness of insulation is 4 cm.
=
+ 4
= 4+4
= 8 cm
is the heat transfer coefficient of convection inside,
is the heat transfer coefficient of convection outside.
The heat transfer rate between ambient and steam is
watt
= watt
= watt
q = 15999.86 watt
The total amount of daily heat transfer = 15999.86 × 86400
= 1382.387904 watt
= 1382.38 M w
The total amount of daily heat transfer is 1382.38 M w.
b) The temperature on the outside surface of the gypsum plaster insulation.
q =
15999.86
- 10 = 7.96
= 17.96 ° C.