Answer:
option (a). The surface area and volume of a body of rotation
is the correct option
Explanation:
Theorems of Pappus and Guldinus are used to find the surface area and volume of a revolving body. It is neither applicable for surface areas and volumes of a symmetric body nor it helps to find the overall mass of any body. Thus, it can help to calculate the surface area and volume of any body rotated in 2-D frame(or any 2-D curve).
It is given or calculated as the product of area, perpendicular distance from the axis and length of the 2-D curve.
Answer:
Weight(lb): 10
Flat fee(cents): 75
Cents per pound: 25
Shipping cost(cents): 325
Explanation:
we run this as a jave programming language
import java.util.Scanner;
public class Shipping Calculator {
public static void main (String [] args) {
int shipWeightPounds = 10;
int shipCostCents = 0;
final int FLAT_FEE_CENTS = 75;
final int CENTS_PER_POUND = 25;
shipCostCents = FLAT_FEE_CENTS + CENTS_PER_POUND * shipWeightPound
/* look up the solutioin above */
System.out.println("Weight(lb): " + shipWeightPounds);
System.out.println("Flat fee(cents): " + FLAT_FEE_CENTS);
System.out.println("Cents per pound: " + CENTS_PER_POUND);
System.out.println("Shipping cost(cents): " + shipCostCents);
}
}
Answer:
- hoop stress
- longitudinal stress
- material used
all this could led to the failure of the garden hose and the tear along the length
Explanation:
For the flow of water to occur in any equipment, water has to flow from a high pressure to a low pressure. considering the pipe, water is flowing at a constant pressure of 30 psi inside the pipe which is assumed to be higher than the allowable operating pressure of the pipe. but the greatest change in pressure will occur at the end of the hose because at that point the water is trying to leave the hose into the atmosphere, therefore the great change in pressure along the length of the hose closest to the end of the hose will cause a tear there. also the other factors that might lead to the failure of the garden hose includes :
hoop stress ( which acts along the circumference of the pipe):
αh = 
EQUATION 1
and Longitudinal stress ( acting along the length of the pipe )
αl = 
EQUATION 2
where p = water pressure inside the hose
d = diameter of hose, T = thickness of hose
we can as well attribute the failure of the hose to the material used in making the hose .
assume for a thin cylindrical pipe material used to be
≥ 20
insert this value into equation 1
αh = 
= 60/2 = 30 psi
the allowable hoop stress was developed by the material which could have also led to the failure of the garden hose
Answer:
Vc2= V(l+e) ^2/4
Vg2= V(l-e^2)/4
Explanation:
Conservation momentum, when ball A strikes Ball B
Where,
M= Mass
V= Velocity
Ma(VA)1+ Mg(Vg)2= Ma(Va)2+ Ma(Vg)2
MV + 0= MVg2
Coefficient of restitution =
e= (Vg)2- (Va)2/(Va)1- (Vg)1
e= (Vg)2- (Va)2/ V-0
Solving equation 1 and 2 yield
(Va)2= V(l-e) /2
(Vg)2= V(l+e)/2
Conservative momentum when ball b strikes c
Mg(Vg)2+Mc(Vc)1 = Mg(Vg)3+Mc(Vc)2
=> M[V(l+e) /2] + 0 = M(Vg)3 + M(Vc) 2
Coefficient of Restitution,
e= (Vc)2 - (Vg)2/(Vg)2- (Vc)1
=> e= (Vc)2 - (Vg)2/V(l+e) /2
Solving equation 3 and 4,
Vc2= V(l+e) ^2/4
Vg2= V(l-e^2)/4
