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rosijanka [135]
2 years ago
14

Find the 55th term in the following arithmetic sequence -102, -98, -94, -90

Mathematics
1 answer:
ololo11 [35]2 years ago
6 0

Answer:

114

Step-by-step explanation:

-102,-98,-94,-90.......

lets give the numbers a name : T ,

and the number order is 1, 2, 3, 4,5....n

we can see :

Tn=T(n-1)+4;

Tn=T(1)+(n-1)4,T1= -102

now n=55

T(55)= -102+(55-1).4=114

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The entire universe of computer games are made up of:
expeople1 [14]

Answer:

Math properties the programmer had put into the software. The majority of programming software is based in math.

Step-by-step explanation:

The other 3 possible answers make no sense.

1. Pixels with red, green, and blue switches - Seriously???

2. Code randomly created by programmers - Seriously???

3. The fundamental properties of physics which consist of numbers and constants (numbers and constants are the same thing and physics has virtually nothing to do with programming)

4 0
2 years ago
8.3.7 From the data on the pH of rain in Ingham County, Michigan: 5.47 5.37 5.38 4.63 5.37 3.74 3.71 4.96 4.64 5.11 5.65 5.39 4.
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Answer:

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3 0
2 years ago
A rectangle has a length of (3.2a + 0.18b)centimeters.The width is half the length. Sasha writes the expression (12.8a + 0.72b)
jeka94
The width is half the length, so is
  width = (1/2)*length
  width = (1/2)*(<span>3.2a + 0.18b) cm
  width = (1.6a +0.09b) cm

The perimeter of the rectangle is twice the sum of length and width.
  perimeter = 2*(length + width)
  perimeter = 2*((3.2a +0.18b) cm + (1.6a +0.09b) cm)
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Sasha did not get this answer, so apparently ...
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8 0
1 year ago
Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
lakkis [162]

Answer:

4.979044478499338 × 10²⁶

Step-by-step explanation:

Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.

Combination factorial is define by  ⁿCr = \frac{n!}{(n-r)!r!}

21 group of mice receiving Drug A  can be selected in ⁶⁰C₂₁ = \frac{60!}{21!39!}

(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug

Drug B 21 mice can be chosen with ³⁹C₂₁ = \frac{39!}{21!18!}

( 39 - 21 = 18)  remained for control with ¹⁸C₁₈ = \frac{18!}{18!0!}

The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = \frac{60!}{21!39!} × \frac{39!}{21!18!} × \frac{18!}{18!0!} = 4.979044478499338 × 10²⁶

8 0
1 year ago
2. In the product of (4a3 + 5a2 – 11a) and (-15 + 3a – 7a2), the co-efficient of a4 is …………………… .
vekshin1

Answer:

- 23

Step-by-step explanation:

We could do this the long way and expand the whole product or note that the a^{4} terms arise from the product of the a³ and a terms and the product of the a² and a² terms, that is

4a³ × 3a = 12a^{4}

+ 5a² × - 7a² = - 35a^{4}

Summing gives

12a^{4} - 35a^{4} = - 23a^{4}

with coefficient - 23

5 0
2 years ago
Read 2 more answers
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