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2 years ago

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The number of children in each family on a particular city block is shown in the dot plot: Dot plot with Number of Children Per

Family on the x axis and Number of Families on the y axis. 1 dot over 0, 3 dots over 1, 5 dots over 2, 2 dots over 3, 2 dots over 4, and 3 dots over 5 Which histogram represents the dot plot data?

2 answers:

sasho [114]2 years ago

7 0

Answer:

that is the answer hope it helps

Step-by-step explanation:

it;s A.

Crank2 years ago

5 0

Answer:

Step-by-step explanation:

Hi,

I think the options are missing for this question.

The x-axis shows the number of children per family and y-axis shows the frequency or number of families with respective number of children.

A histogram simply displays the data with bars of different heights. The higher the frequency, the taller the bar of the histogram and vice versa.

Your histogram should look like this.

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Which statements are true regarding triangle LMN? Check all that apply.

dimaraw [331]

Answer:

$NM = x$

$LM = x\sqrt{2}$

$tan (45) = 1$

Step-by-step explanation:

Step 1: Pythagoras Theorem

Pythagoras theorem relates the three sides of the triangle in such a way that the sum of the square of base and perpendicular is equal to hypotenuse, such as:

$LM^{2} =LN^{2} +NM^{2}$

Step 2: Trigonometric Functions

Only for a right angle triangle following three trigonometric relations are valid

$sin (\theta) = \frac{opposite}{hypotenuse}$

$cos (\theta) = \frac{adjacent}{hypotenuse}$

$tan (\theta)=\frac{sin (\theta)}{cos (\theta)} = \frac{opposite}{adjacent}$

Step 3: Verifying all the possible answers

A: Since, LN = x and using $tan (45) =1$

we can calculate

$tan (\theta)= \frac{opposite}{adjacent}$

$tan (45)= \frac{NM}{x} =1$

therefore, NM = x (true)

B: As NM = x therefore it can not be equal to $x\sqrt{2\\}$ .

C: Using Pythagoras Theorem

$LM^{2} =LN^{2} +NM^{2}$

$LM^{2} =x^{2} +x^{2}$

$LM^{2} =2x^{2}$

$LM = \sqrt{2x^{2}} = x\sqrt{2}$

It can also be proved using trigonometric relation

$cos (45) = \frac{x}{LM}$

$LM = \frac{x}{cos (45)}$

As, $\frac{1}{cos (45)}= \sqrt{2}$

Therefore

$LM = x\sqrt{2}$

D and E:

Using same approach similar to part A

Since, LN = x and NM = x

we can calculate

$tan (\theta)= \frac{opposite}{adjacent}$

$tan (45)= \frac{x}{x} =1$

Therefore, $tan (45) = 1$ and not equal to $\frac{\sqrt{2} }{2}$

3 0

2 years ago

Read 2 more answers

Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?

irakobra [83]

First, note that $m\angle A+m\angle C=90^{\circ}.$ Then

$m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.$

Consider all options:

A.

$\tan A=\dfrac{\sin A}{\sin C}$

By the definition,

$\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.$

Now

$\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.$

Option A is true.

B.

$\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.$

Then

$\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.$

Option B is false.

3.

$\sin C = \dfrac{\cos A}{\tan C}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

Now

$\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.$

Option C is false.

D.

$\cos A=\tan C.$

By the definition,

$\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.$

As you can see $\cos A\neq \tan C$ and option D is not true.

E.

$\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.$

By the definition,

$\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.$

Then

$\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.$

This option is false.

8 0

2 years ago

Read 2 more answers

a coin must have diameter of 27.13 millimeters.To the nearest hundredth, what is the circumference of this coin millimeters

Bas_tet [7]

To find the circumference, you will use the formula for finding circumference of a circle.

I used the true value of pi for the calculations.

C = pi x d
pi x 27.13
C = 85.77mm

4 0

2 years ago

Find the length of the longest line segment that can be drawn on a rectangular board 3.07m by 2.24m

nikklg [1K]

For rectangle
l=3.07m
b=2.24m
so longest side that can be drawn is diagonal of rectangular board
=squareroot l^2+b^2
=squareroot3.07^2+2.24^2
=squareroot9.4249+5.0176
=squareroot14.4425
=3.80
So longest line that can be drawn in rectangular board is 3.80m

3 0

2 years ago

This star is made up of 4 equilateral triangles of equal area and a square.

pentagon [3]

Answer:

24 cm

Step-by-step explanation:

Given: Picture of the star is made up of 4 unshaded equilateral triangles of equal area and a shaded square.

Area of the shaded region (square) = $9\,\, cm^2$

To find: the perimeter of the star

Solution:

Area of the shaded region (square) = $9\,\, cm^2$

Area of square = $(side)^2$

$(side)^2=9\\side=3\,\,cm$

As each equilateral triangle has side lengths that are the same as the side length of the square,

length of side of the star = 3 cm

Perimeter is the sum of lengths of the sides.

Perimeter of star = sum of 8 sides of the star

= 8 × 3 = 24 cm

4 0

2 years ago