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2 years ago

Amy bakes 250 chocolate chip cookies and sells these in boxes of 9.

Mathematics

2 answers:

vazorg [7]2 years ago

8 0

Answer: she can get 27 boxes of cookies and 7 would be leftover.

Step-by-step explanation:

The total number of cookies that Amy baked is 250. She sells them in boxes of nine. Therefore, the total number of boxes containing 9 cookies each that she can get from a total of 250 cookies would be

250/9 = 27.778

This means that she can only get 27 boxes of cookies.

The number of cookies that would be left over is

250 - (27 × 9) = 250 - 243

= 7

Inga [223]2 years ago

6 0

27 full boxes

7 cookies leftover

27r7

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2 years ago

A garden supply store sells two types of lawn mowers. Total ales of mowers for the year were $8379.70. The total number of mower

Anestetic [448]

Answer:

The number of small mowers are 19 and the large mowers are 11.

Step-by-step explanation:

Given:

A garden supply store sells two types of lawn mowers. Total sales of mowers for the year were $8379.70. The total number of mowers sold the 30. The small mower cost $249.99 and the large mower costs $329.99.

Now, to find the number of each type of mower sold.

Let the number of small mower be $x.$

And the number of large mower be $y.$

So, total number of mowers are:

$x+y=30$

$x=30-y\ \ \ ....(1)$

Now, the total sales of mowers are:

$249.99(x)+329.99(y)=8379.70$

Substituting the value of $x$ from equation (1) we get:

$249.99(30-y)+329.99y=8379.70$

$7499.7-249.99y+329.99y=8379.70$

$7499.7+80y=8379.70$

<em>Subtracting both sides by 7499.7 we get:</em>

$80y=880$

<em>Dividing both sides by 80 we get:</em>

$y=11.$

The number of large mower = 11.

Now, to get the number of small mowers we substitute the value of $y$ in equation ( 1 ):

$x=30-y\\x=30-11\\x=19.$

The number of small mower = 19.

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2 years ago

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<h2><u><em>Answer: </em></u></h2><h2><u><em> </em></u></h2>

ASA and AAS

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We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

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Answer:

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