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erik [133]
2 years ago
4

A student conducts an experiment that involves the transfer of energy. The student places one metal spoon, one plastic spoon, an

d one wooden spoon in a glass that contains hot water. A small pat of butter is placed onto each spoon. The pat of butter on the metal spoon is the first to melt and slide down the spoon. Which of the following descriptions BEST explains the results of this experiment?
The metal material has a rigid structure with little molecular movement, allowing heat to transfer directly from one end of the spoon to the other.

The metal material condenses steam quickly, allowing the heat from the steam to warm both the metal spoon and the butter on it the fastest.

The metal material transfers energy from molecular collisions up the length of the spoon the fastest, allowing the heat to reach the butter the fastest.

The metal material is made up of well-spaced molecules, allowing the heat to travel through the air pockets and reach the butter the fastest.
Chemistry
1 answer:
sergij07 [2.7K]2 years ago
4 0

Answer:

The metal material transfers energy from molecular collisions up the length of the spoon the fastest, allowing the heat to reach the butter the fastest.

Explanation:

During this experiment, the pat of butter on the metal spoon is the first to melt and slide down the spoon rather than plastic and wood spoon. There are two reasons for this:

1) the close packing of the metal ions in the metal.

2) metal has free electrons that carry kinetic energy and transfer it by collision faster than plastic or wood.

Metals are a conductor of heat than plastic and wood because of its molecular composition

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Hydrogen gas(H2) has a molar mass of 2 g. Molar mass of a substance is defined as the mass of 1 mole of that substance. And by 1 mole it is meant a collection of 6.022*10^23 particles of that substance.

So number of moles of H2 are 0.5 in this case. And thus it means there are (6.022*10^23)*0.5 particles( here they are molecules) in 1g of H2.
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2 years ago
Silver nitrate and aluminum chloride react with each other by exchanging anions: 3agno3 (aq) + alcl3 (aq) → al(no3)3 (aq) + 3agc
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Silver nitrate and aluminum chloride react with each other by exchanging anions: 3agno3 (aq) + alcl3 (aq) → al(no3)3 (aq) + 3agcl (s) what mass in grams of agcl is produced when 4.22 g of agno3 react with 7.73 g of alcl3?
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Latent heat of vaporization is used to (1 Point) (a) overcome the forces of attraction between molecules in solid-state. (b) inc
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Answer:

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Explanation:

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4 0
2 years ago
A sample of gasoline contains various hydrocarbons, which comprise atoms of carbon, hydrogen, and oxygen. The hydrocarbons mix t
Naddika [18.5K]

Answer:

  • mixture
  • homogenous mixture  (of hydrocarbons)
  • compound

Explanation:

Mixture can be easily separated by physical methods. Homogeneity and heterogeneity of a mixture is determined by whether the components there in are in a single phase and evenly distributed or not.

A solution has a solute evenly dissolved in  solvent to form a liquid substance.

An element is the basic form of  substance which cannot be broke down into any other simpler unit.  

I hope this was helpful.

4 0
2 years ago
The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p
zysi [14]

Answer :    q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})  (in terms of mass)

or, q=\Delta H_{fusion}\times Moles     (in terms of moles)

Now we have to calculate the value of q.

q=6020J/mole\times 1Mole=6020J

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of \Delta e=0

Now we have to calculate the value of w.

Formula used :    \Delta e=q+w

where, q is heat required, w is work done and \Delta e is internal energy.

Now put all the given values in above formula, we get

0=6020J+w

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0
2 years ago
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