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kati45 [8]
2 years ago
8

A bank finds that the average number of people waiting in line during lunch hour is 10. On average, during this period, 2 people

per minute leave the bank after receiving service.
On average, how long do bank customers wait in line?
Mathematics
1 answer:
mihalych1998 [28]2 years ago
5 0

Answer:

5 minutes.

Step-by-step explanation:

We have been given that a bank finds that the average number of people waiting in line during lunch hour is 10. On average, during this period, 2 people per minute leave the bank after receiving service.

We will use flow time formula to solve our given problem.

\text{Flow time}=\frac{\text{Number of units produced}}{\text{Duration of time period}}

\text{Flow time}=\frac{10}{2}

\text{Flow time}=5

Therefore, on average bank customers wait in line for 5 minutes.

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erik [133]

they are 80 feet apart.


 see picture for solution

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2 years ago
Ruth Ann wants to research two different careers, medical doctor and astronaut.
elixir [45]

Answer: visit the US Bureau of Labor Statistics website to find information on both careers

The career section

hope this helped :)

Step-by-step explanation: there is none

3 0
2 years ago
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Miyoko's goal is to earn more than \$950$950dollar sign, 950 this week. She earns \$250$250dollar sign, 250 for every day she wo
GrogVix [38]

$250 c+ $ 180 g > $ 950

<u>Step-by-step explanation:</u>

As a cryptographer (c), Miyoko earns per day = $ 250

As a geologist (g) , Miyoko earns per day = $ 180

So the equation comes to be $250 c+ $ 180 g = $ 950

The equation can be rewritten to find c as, (950-180 g) / 250

The equation can be rewritten to find g as, (950 - 250 c) / 180

Plugin different values of c and g in the above 2 equations, we can find that ,

To achieve the goal, Miyoko requires to be a geologist for 3 days and crpytographist for 2 days.

5 0
2 years ago
Sunita bought a 10 kg box of grapes from the market. She gave 3 1/2 kg of her grapes to her friend Reena and 2 1/4 kg to Anita.
kirill115 [55]

Answer:

17/4 kg

Step-by-step explanation:

Sunita has = 10kg of grapes

Quantity given out :

To Reena =3 1/2

7/2 kg

To Anita =2 1/4

9/4 kg

Total quantity of grape given out

7/2+9/4

(14+9)/4

23/4

Quantity left after giving out = Total quantity of grape before giving out minus quantity of grape given out

10/1 - 23/4

40-23)/4

= 17/4 or 4 1/4

Hence, she has 17/4 kg of grape left with her

5 0
2 years ago
Without properly working spark plugs, a vehicle will not run. For a specific vehicle, the spark plugs are supposed to have a gap
Salsk061 [2.6K]

Answer:

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the mean of the Normal distribution = 4.1mm</em>

<em>Given that the standard deviation of the Normal distribution = 0.0075mm</em>

<em>Let 'X' be the random variable in a normal distribution</em>

Given that X₁ = 3.9mm

Z_{1} = \frac{X_{1} -mean}{S.D}

Z_{1} = \frac{3.9 -4.1}{0.075} =  -2.666

Given that X₂ = 4.3mm

Z_{2} = \frac{X_{2} -mean}{S.D}

Z_{1} = \frac{4.3 -4.1}{0.075} =  2.666

<u><em>Step(ii):-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3) = P(-2.666≤Z≤2.666)</em>

<em>                      = P(Z≤2.666)-P(Z≤-2.666)</em>

<em>                     = 0.5 +A(2.666) - (0.5-A(2.666)</em>

<em>                    = 2 × A(2.666)</em>

<em>                  = 2×0.4961</em>

<em>                  = 0.9922</em>

<u><em>Final answer:-</em></u>

<em>The probability that the spark plugs are supposed to have a gap between 3.9mm and 4.3mm.</em>

<em>P(3.9≤X≤4.3)  = 0.9922</em>

<em></em>

3 0
1 year ago
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